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【LeetCode】027. Remove Element

时间:2017-04-23 14:24:09      阅读:185      评论:0      收藏:0      [点我收藏+]

标签:oca   har   size   val   example   return   constant   ace   难度   

题目:

Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.

Example:

Given input array nums = [3,2,2,3], val = 3

  

题解:

  这个题和之前的题类似,难度不大

Solution 1 ()

class Solution {
public:
    int removeElement(vector<int>& nums, int val) {
        int n = nums.size();
        int cnt = 0;
        for(int i=0; i<n;i++) {
            if(nums[i] == val) cnt++;
            else {
                nums[i - cnt] = nums[i];
            }
        } 
        return n - cnt;
    }
};

 

Solution 2 ()

class Solution {
public:
    int removeElement(vector<int>& nums, int val) {
        int len = 0;
        for (int i = 0; i < nums.size(); ++i) {
            if (nums[i] != val) nums[len++] = nums[i];
        }
        return len;
    }
};

 

【LeetCode】027. Remove Element

标签:oca   har   size   val   example   return   constant   ace   难度   

原文地址:http://www.cnblogs.com/Atanisi/p/6752342.html

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