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USACO Chapter 1 Section 1.3

时间:2017-04-25 23:22:25      阅读:227      评论:0      收藏:0      [点我收藏+]

标签:pen   stdin   sizeof   section   i++   while   open   count   ast   

 

 

技术分享
 1 /*
 2 ID:xiekeyi1
 3 PROG:milk
 4 LANG:C++
 5  */
 6 
 7 #include<bits/stdc++.h>
 8 using namespace std ;
 9 
10 const int maxm = 5050 ; 
11 
12 struct P
13 {
14     int price ; 
15     int amount ;
16 }a[maxm];
17 
18 bool cmp( struct P a , struct P b )
19 {
20     return ( a.price < b.price ) ;
21 }
22 
23 
24 int main()
25 {
26     freopen("milk.in","r",stdin);
27     freopen("milk.out","w",stdout);
28     ios::sync_with_stdio(false);
29     cin.tie(false) ; 
30     int n ;
31     int m ;
32     cin >> n >> m ;
33     for( int i = 1 ; i <= m ; i++)
34         cin >> a[i].price >> a[i].amount ;
35     sort(a+1,a+1+m,cmp);
36     int ans = 0 ;
37     int cnt = 1 ; 
38     while( n != 0 )
39     {
40         if( a[cnt].amount <= n )
41         {
42             n -= a[cnt].amount;
43             ans += a[cnt].amount * a[cnt].price;
44             a[cnt].amount = 0 ;
45         }
46         else 
47         {
48             ans+= n * a[cnt].price ;
49             a[cnt].amount -= n ;
50             n = 0 ;
51         }
52         cnt++;
53     }
54 
55     cout << ans << endl ;
56     return 0 ; 
57 }
1milk

 

 

 

技术分享
 1 /*
 2 ID:xiekeyi1
 3 PROG:barn1
 4 LANG:C++
 5  */
 6 
 7 #include<bits/stdc++.h>
 8 using namespace std ; 
 9 int a[210]; 
10 int maxr = 0 ; 
11 int minl = 999 ; 
12 void filling( int l , int r )
13 {
14     for( int i = l ; i <= r ; i++ )
15         a[i] = 3 ; 
16 }
17 
18 
19 int func()
20 {
21     int l = 0 , r = 0 ;
22     int cnt = 0 ;
23     for( int i = minl ; i <= maxr ; i++)
24     {
25         if( a[i] != 0 )
26             continue ;
27         int temp = 1 ; 
28         int j ; 
29         for( j = i + 1 ; j <= maxr ; j++)
30         {
31             if( a[j]  == 0 )
32                 temp++;
33             else
34                 break ; 
35         }
36         
37         if( temp >=  ( r - l + 1 )  )
38             l = i , r = j - 1  , cnt = temp ; ;
39     }
40     
41     filling( l , r ) ;
42     return cnt ; 
43 }
44 
45 
46 int main()
47 {
48 
49     freopen("barn1.in","r",stdin);
50     freopen("barn1.out","w",stdout); 
51     int m , s , c ;
52     cin >> m >> s >> c ;
53     memset( a , 0 , sizeof(a) )  ;
54     int ans = 0 , mm = 1 ; 
55     for( int i = 1 ; i <= c ; i++)
56     {
57         int t ;
58         cin >> t ;
59         a[t] = 1 ;
60         maxr = max( t , maxr ) ; 
61         minl = min( minl , t ) ; 
62     }
63     ans = maxr - minl + 1 ; 
64 
65     while( mm < m && mm < c )
66     {
67         ans = ans -  func() ;
68         mm++;
69     }
70 
71     cout << ans << endl ; 
72     return 0 ; 
73 
74 }
2barn

 

 

技术分享
 1 /*
 2 ID:xiekeyi1
 3 PROG:crypt1
 4 LANG:C++
 5  */
 6 
 7 #include<bits/stdc++.h>
 8 using namespace std ;
 9 int a[100];
10 set<int> b ;
11 
12 bool judge( int n )
13 {
14     while( n != 0 )
15     {
16         if( !b.count( n % 10 ) )
17             return false ;
18         n /= 10 ;
19     }
20 
21     return true ; 
22 }
23 
24 
25 int main()
26 {
27     freopen("crypt1.in","r",stdin);
28     freopen("crypt1.out","w",stdout);
29     int n ;
30     cin >> n ;
31     for( int i = 1 ; i <= n ; i++)
32     {
33         cin >> a[i];
34         b.insert(a[i]) ;
35     }
36 
37     int ans = 0 ;
38 
39     int q = 0 , w = 0 , e = 0 ; 
40     for( int i = 1 ; i <= n ; i++)
41     {
42         for( int j = 1 ; j <= n ; j++)
43         {
44             for( int k = 1 ; k <= n ; k++)
45             {
46                 for( int l = 1 ; l <= n ; l++)
47                 {
48                     for( int m = 1 ; m <= n ; m++)
49                     {
50                         q = ( a[i] * 100 + a[j] * 10 + a[k] ) * a[m] ;
51                         w = ( a[i] * 100 + a[j] * 10 + a[k] ) *  a[l];
52                         e = ( a[i] * 100 + a[j] * 10 + a[k] ) * ( a[l] * 10 + a[m] ) ;
53                         if( w < 1000 && q < 1000 && e < 10000 && judge(q) && judge(w) && judge(e) )
54                         {
55                             ans++;
56                             //cout << q << ‘ ‘ << w << ‘ ‘ << e << endl ; 
57                         }
58 
59                     }
60                 }
61             }
62         }
63     }
64 
65     cout << ans << endl ;
66     return 0 ; 
67 }
3crypt

 

 

技术分享
/*
ID:xiekeyi1
PROG:combo
LANG:C++
 */

#include<bits/stdc++.h>
using namespace std ;


int n ;
int john[4] , master[4];
int similar( int a , int b )
{

    if( a >= n - 1 && b <= n -1 )
        return min( abs( a - b ) , abs( a - n - b ) ) ;
    if( b >= n - 1 && a <= n - 1 )
        return min( abs( a - b ) , abs( b - n - a ) ) ;

    return abs( a - b ) ; 
}

//int s( int a[] , int b )
//{
//    int minn  = 99999999 ;
//    for( int i = 1 ; i <= 3 ; i++ )
//        minn = min( minn , similar( b , a[i] ) ) ;
//
//    return minn ;
//}

bool judge( int a , int b , int c )
{
    int cnt = 0 ;
    if( similar( john[1] , a ) <= 2 )
        cnt++;
    if( similar( john[2] , b ) <= 2 )
        cnt++;
    if( similar( john[3] , c ) <= 2 )
        cnt++;
    if( cnt == 3 )
        return true ;
    
    cnt = 0 ;
    if( similar( master[1] , a ) <= 2 )
        cnt++;
    if( similar( master[2] , b ) <= 2 )
        cnt++;
    if( similar( master[3] , c ) <= 2 )
        cnt++;
    if( cnt == 3 )
        return true ; 

    return false ; 
}

int main()
{
    freopen("combo.in","r",stdin);
    freopen("combo.out","w",stdout);
    cin >> n ;
    cin >> john[1] >> john[2] >> john[3] 
        >> master[1] >> master[2] >> master[3] ;
    int ans = 0 ; 
    for( int i = 1 ; i <= n ; i++ ) 
    {
        for( int j = 1 ; j <= n ; j++)
        {
            for( int k = 1 ; k <= n ; k++)
            {
                if( judge( i , j , k ) )
                {
                    ans++ ;
                //    cout << i << ‘ ‘ <<  j << ‘ ‘ <<  k << endl ;
                }


            }
        }
    }

    cout << ans << endl ;
    return 0 ; 
}
4combo

 

 

 

技术分享
 1 /*
 2 ID:xiekeyi1
 3 PROG:wormhole
 4 LANG:C++
 5  */
 6 
 7 #include<bits/stdc++.h>
 8 using namespace std ;
 9 int n ;
10 int ans = 0 ;
11 int b[15] ;
12 struct node
13 {
14     int x , y ;
15 }a[15];
16 
17 bool cmp( struct node a , struct node b )
18 {
19     if( a.y < b.y )
20         return 1 ;
21     else if( a.y == b.y)
22         return a.x < b.x ;
23     else
24         return false ;
25 }
26 
27 
28 
29 bool doit( int num , int x , int begin , int into )
30 {
31     if( num != 1 && begin == x && into == 0 )
32         return true ;
33     else if( into == 0 ) 
34     {
35         if( a[x].y == a[x+1].y )
36         {
37             return doit( num+1,x+1,begin,1 );
38         }
39         else 
40             return false ;
41     }
42 
43     else 
44     {
45         return doit( num+1, b[x] , begin , 0 ) ;
46     }
47 }
48 
49 
50 bool judge()
51 {
52     for( int i = 1 ; i <= n ; i++)
53         if( doit( 1 , i , i , 0 ) == 1 )
54             return true ;
55     return false ; 
56 }
57 
58 void mpair( int x )
59 {
60     if ( x == n + 1 )
61     {
62         if( judge() ==  1)
63             ans++;
64         return ; 
65     }
66 
67     else if( b[x] == 0 )
68     {
69         for( int i = x + 1 ; i <= n ; i++)
70         {
71             if( b[i] == 0 )
72             {
73                 b[x] = i ;
74                 b[i] = x ;
75                 mpair(x+1);
76                 b[x] = 0 ;
77                 b[i] = 0 ;
78             }
79         }
80     }
81 
82     else
83         mpair(x+1);
84 }
85 
86 int main()
87 {
88     freopen("wormhole.in","r",stdin);
89     freopen("wormhole.out","w",stdout);
90     cin >> n ;
91     for( int i = 1 ; i <= n ; i++)
92         cin >> a[i].x >> a[i].y ;
93     sort(a+1,a+1+n,cmp) ;
94 
95     mpair(1);
96     cout << ans << endl ;
97     return 0  ; 
98 }
5wormhole

 

 

 

技术分享
 1 /*
 2 ID:xiekeyi1
 3 PROG: skidesign 
 4 LANG:C++
 5 */
 6 
 7 #include<bits/stdc++.h>
 8 using namespace std ;
 9 const int maxn = 1010 ;
10 int a[maxn];
11 
12 
13 int main()
14 {
15     freopen("skidesign.in","r",stdin);
16     freopen("skidesign.out","w",stdout);
17     int  n ; 
18     int ans = 0x7FFFFFFF; 
19 
20     cin >> n ;
21     for( int i = 1 ; i <= n ; i++)
22         cin >> a[i] ; 
23     sort( a+1 , a+1+n ) ;
24     for( int i = a[1] ; i <= a[n] ; i++)
25     {
26         int temp = 0 ; 
27         for( int j = 1 ; j <= n ; j++)
28         {
29             if( a[j] < i )
30                 temp+= static_cast<int> ( pow( abs( i - a[j] ) , 2 ) ) ;
31             if( a[j] > i + 17 ) 
32                 temp += static_cast<int> ( pow( abs( i + 17 - a[j] ) , 2 ) ) ;
33         }
34 
35         ans = min( ans , temp ) ;
36     }
37     cout << ans << endl ;
38     return 0 ; 
39 }
6skidesign

 

USACO Chapter 1 Section 1.3

标签:pen   stdin   sizeof   section   i++   while   open   count   ast   

原文地址:http://www.cnblogs.com/xiekeyi98/p/6764899.html

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