标签:tco head 条件 bin sort nbsp leetcode code ack
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
递归进行。每次找到排序数组的中点,中点左边的子排序数组构成左子树,中点右边的子排序数组构成右子树。
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode sortedArrayToBST(int[] nums) { if(nums.length==0){ return null; } TreeNode head=construct(nums,0,nums.length-1); return head; } public TreeNode construct(int[] nums,int low,int high){ if(low>high){ //边界条件 return null; } int mid=low+(high-low)/2; TreeNode node=new TreeNode(nums[mid]); node.left=construct(nums,low,mid-1); node.right=construct(nums,mid+1,high); return node; } }
leetcode_108 Convert Sorted Array to Binary Search Tree(Tree)
标签:tco head 条件 bin sort nbsp leetcode code ack
原文地址:http://www.cnblogs.com/ytq1016/p/6775580.html