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HDU 1890 Robotic Sort (Splay)

时间:2017-04-28 23:42:08      阅读:255      评论:0      收藏:0      [点我收藏+]

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题意:将一列数字排序  排序规则是  每次找到最小值的位置loc  将1~loc所有数字颠倒  然后删掉第一位  直到排好序  排序要求是稳定的。

析:直接用splay来维护最小值,然后插入删除即可。

代码如下:

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
#include <cctype>
#include <cmath>
#include <stack>
#include <sstream>
#define debug() puts("++++");
#define gcd(a, b) __gcd(a, b)
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define freopenr freopen("in.txt", "r", stdin)
#define freopenw freopen("out.txt", "w", stdout)
using namespace std;

typedef long long LL;
typedef unsigned long long ULL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const LL LNF = 1e16;
const double inf = 0x3f3f3f3f3f3f;
const double PI = acos(-1.0);
const double eps = 1e-8;
const int maxn = 1e5 + 10;
const int mod = 1e9 + 7;
const int dr[] = {-1, 0, 1, 0};
const int dc[] = {0, 1, 0, -1};
const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
int n, m;
const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
inline bool is_in(int r, int c){
  return r >= 0 && r < n && c >= 0 && c < m;
}
struct Node{
  int val, id;
  bool operator < (const Node &p) const{
    return val < p.val || (val == p.val && id < p.id);
  }
  bool operator == (const Node &p) const{
    return val == p.val && id == p.id;
  }
};
Node a[maxn], key[maxn], minv[maxn];

#define Key_value ch[ch[root][1]][0]
int pre[maxn], ch[maxn][2], sz[maxn];
int root, tot1;
int rev[maxn];
int s[maxn], tot2;

void NewNode(int &rt, int fa, Node x){
  if(tot2)  rt = s[tot2--];
  else  rt = ++tot1;
  pre[rt] = fa;
  key[rt] = x;
  ch[rt][0] = ch[rt][1] = 0;
  rev[rt] = 0;
  sz[rt] = 1;
}

void push_up(int rt){
  int l = ch[rt][0], r = ch[rt][1];
  sz[rt] = sz[l] + sz[r] + 1;
  minv[rt] = key[rt];
  if(minv[l] < minv[rt])  minv[rt] = minv[l];
  if(minv[r] < minv[rt])  minv[rt] = minv[r];
}

void update_rev(int rt){
  if(!rt)  return ;
  swap(ch[rt][0], ch[rt][1]);
  rev[rt] ^= 1;
}

void push_down(int rt){
  if(rev[rt]){
    update_rev(ch[rt][0]);
    update_rev(ch[rt][1]);
    rev[rt] = 0;
  }
}

void Build(int &rt, int l, int r, int fa){
  if(l > r)  return ;
  int m = l+r >> 1;
  NewNode(rt, fa, a[m]);
  Build(ch[rt][0], l, m-1, rt);
  Build(ch[rt][1], m+1, r, rt);
  push_up(rt);
}

void Init(){
  tot1 = root = tot2 = 0;
  ch[root][0] = ch[root][1] = sz[root] = pre[root] = 0;
  rev[root] = 0;  key[root] = (Node){INF, INF};
  NewNode(root, 0, (Node){INF, INF});
  NewNode(ch[root][1], root, (Node){INF, INF});
  for(int i = 0; i < n; ++i){
    scanf("%d", &a[i].val);
    a[i].id = i+1;
  }
  Build(Key_value, 0, n-1, ch[root][1]);
  push_up(ch[root][1]);
  push_up(root);
}

int Get_kth(int rt, int k){
  push_down(rt);
  int t = sz[ch[rt][0]] + 1;
  if(t == k)  return rt;
  if(t > k)  return Get_kth(ch[rt][0], k);
  return Get_kth(ch[rt][1], k-t);
}

void Rotate(int x, int k){
  int y = pre[x];
  push_down(y);
  push_down(x);
  ch[y][!k] = ch[x][k];
  pre[ch[x][k]] = y;
  if(pre[y])  ch[pre[y]][ch[pre[y]][1]==y] = x;
  pre[x] = pre[y];
  ch[x][k] = y;
  pre[y] = x;
  push_up(y);
}

void Splay(int rt, int goal){
  push_down(rt);
  while(pre[rt] != goal){
    if(pre[pre[rt]] == goal){
      push_down(pre[rt]);
      push_down(rt);
      Rotate(rt, ch[pre[rt]][0] == rt);
      continue;
    }
    push_down(pre[pre[rt]]);
    push_down(pre[rt]);
    push_down(rt);
    int y = pre[rt];
    int k = ch[pre[y]][0] == y;
    if(ch[y][k] == rt){
      Rotate(rt, !k);
      Rotate(rt, k);
    }
    else{
      Rotate(y, k);
      Rotate(rt, k);
    }
  }
  push_up(rt);
  if(goal == 0)  root = rt;
}

void Insert(int pos, int tot){
  Splay(Get_kth(root, pos+1), 0);
  Splay(Get_kth(root, pos+2), root);
  Build(Key_value, 0, tot-1, ch[root][1]);
  push_up(ch[root][1]);
  push_up(root);
}

void Erase(int rt){
  if(!rt)  return ;
  s[++tot2] = rt;
  Erase(ch[rt][0]);
  Erase(ch[rt][1]);
}


void Reverse(int pos, int tot){
  Splay(Get_kth(root, pos), 0);
  Splay(Get_kth(root, pos+tot+1), root);
  update_rev(Key_value);
  push_up(ch[root][1]);
  push_up(root);
}

int Get_min(int rt, Node x){
  if(key[rt] == x)  return rt;
  if(minv[ch[rt][0]] == x)  return Get_min(ch[rt][0], x);
  return Get_min(ch[rt][1], x);
}

int query(Node x){
  int t = Get_min(root, x);
  Splay(t, 0);
  int ans = sz[ch[root][0]];
  Reverse(1, ans);
  Splay(Get_kth(root, 1), 0);
  Splay(Get_kth(root, 3), root);
  Erase(Key_value);
  pre[Key_value] = 0;
  Key_value = 0;
  push_up(ch[root][1]);
  push_up(root);
  return ans;
}


int main(){
  while(scanf("%d", &n) == 1 && n){
    memset(minv, INF, sizeof minv);
    Init();
    sort(a, a + n);
    for(int i = 0; i < n; ++i){
      if(i)  putchar(‘ ‘);
      printf("%d", query(a[i])+i);
    }
    printf("\n");
  }
  return 0;
}

  

HDU 1890 Robotic Sort (Splay)

标签:wap   代码   scanf   lib   位置   return   ble   tin   ase   

原文地址:http://www.cnblogs.com/dwtfukgv/p/6783441.html

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