标签:php close open mod ati 题解 const pen tar
传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=3918
【题解】
每日至少更一题啊qwq凑任务(迷
明显猜个结论:随便搜环就行了
然后搜环姿势错了我也很无奈啊。。。
# include <stdio.h> # include <string.h> # include <algorithm> // # include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef unsigned long long ull; const int M = 1500000 + 10; const int mod = 1e9+7; # define RG register # define ST static int n, m; int head[M], nxt[M], to[M], tot = 1; inline void add(int u, int v) { ++tot; nxt[tot] = head[u]; head[u] = tot; to[tot] = v; } inline void adde(int u, int v) { add(u, v); add(v, u); } bool vis[M]; int Final; int c[M], cn, p[M]; inline void dfs(int x) { if(p[x] != -1) { printf("%d", x); for (int i=p[x]+1; i<=cn; ++i) { printf(" %d", c[i]); p[c[i]] = -1; } puts(""); cn = p[x]; return; } c[++cn] = x; p[x] = cn; for (int i=head[x]; i; i=nxt[i]) { if(vis[i] || vis[i^1]) continue; head[x] = nxt[i]; vis[i] = 1; dfs(to[i]); if(p[x] == -1) break; } } int main() { scanf("%d%d", &n, &m); for (int i=1; i<=m; ++i) { int u, v; scanf("%d%d", &u, &v); adde(u, v); } for (int i=1; i<=n; ++i) p[i] = -1; for (int i=2; i<=tot; i++) if(!vis[i] && !vis[i^1]) dfs(to[i]); return 0; }
标签:php close open mod ati 题解 const pen tar
原文地址:http://www.cnblogs.com/galaxies/p/bzoj3918.html