标签:expec UI data- des int time import val out
A non-empty zero-indexed array A consisting of N integers is given. Theproduct of triplet (P, Q, R) equates to A[P] * A[Q] * A[R] (0 ≤ P < Q < R < N).
For example, array A such that:
A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6contains the following example triplets:
- (0, 1, 2), product is −3 * 1 * 2 = −6
- (1, 2, 4), product is 1 * 2 * 5 = 10
- (2, 4, 5), product is 2 * 5 * 6 = 60
Your goal is to find the maximal product of any triplet.
Write a function:
class Solution { public int solution(int[] A); }
that, given a non-empty zero-indexed array A, returns the value of the maximal product of any triplet.
For example, given array A such that:
A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6the function should return 60, as the product of triplet (2, 4, 5) is maximal.
Assume that:
- N is an integer within the range [3..100,000];
- each element of array A is an integer within the range [−1,000..1,000].
Complexity:
- expected worst-case time complexity is O(N*log(N));
- expected worst-case space complexity is O(1), beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.
// you can also use imports, for example:
// import java.util.*;
// you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message");
import java.util.Arrays;
import java.lang.Math;
class Solution {
public int solution(int[] A) {
// write your code in Java SE 8
Arrays.sort(A);
int res = A[0] * A[1] * A[2];
res = Math.max(res, A[0] * A[1] *A[A.length-1]);
res = Math.max(res, A[0] * A[A.length-1] *A[A.length-2]);
res = Math.max(res, A[A.length-3] * A[A.length-1] *A[A.length-2]);
return res;
}
}
https://codility.com/demo/results/trainingHWDPP7-ZXQ/
标签:expec UI data- des int time import val out
原文地址:http://www.cnblogs.com/samo/p/6784422.html