图的深度遍历与广度遍历与二叉树的遍历类似,但是因为是图,需要有个数组存一下点是否被遍历过。
/** * 源码名称:GraphIterateMatrix.java * 日期:2014-08-25 * 程序功能:图的深度与广度遍历 * 版权:CopyRight@A2BGeek * 作者:A2BGeek */ import java.util.LinkedList; import java.util.Queue; public class GraphIterateMatrix { private String[] Vnode = { "A", "B", "C", "D", "E", "F", "G", "H", "I" }; private int[][] Edge = { { 0, 1, 0, 0, 0, 1, 1, 0, 0 }, { 1, 0, 1, 0, 0, 0, 1, 0, 1 }, { 0, 1, 0, 1, 0, 0, 0, 0, 1 }, { 0, 0, 1, 0, 1, 0, 1, 1, 1 }, { 0, 0, 0, 1, 0, 1, 0, 1, 0 }, { 1, 0, 0, 0, 1, 0, 1, 0, 0 }, { 0, 1, 0, 1, 0, 1, 0, 1, 0 }, { 0, 0, 0, 1, 1, 0, 1, 0, 0 }, { 0, 1, 1, 1, 0, 0, 0, 0, 0 } }; private int nodeNum = Vnode.length; private boolean[] flag; private Queue<Integer> queue;// for bfs public void Dfs() { flag = new boolean[nodeNum]; for (int i = 0; i < nodeNum; i++) { if (flag[i] == false) { DfsRecursive(i); } } } private void DfsRecursive(int j) { flag[j] = true; System.out.print(Vnode[j] + " "); for (int k = 0; k < nodeNum; k++) { if (Edge[j][k] == 1 && flag[k] == false) { DfsRecursive(k); } } } public void Bfs() { flag = new boolean[nodeNum]; for (int i = 0; i < nodeNum; i++) { if (flag[i] == false) { BfsIterate(i); } } } private void BfsIterate(int i) { flag[i] = true; System.out.print(Vnode[i] + " "); queue = new LinkedList<Integer>(); queue.offer(i); while (!queue.isEmpty()) { int j = queue.poll(); for (int k = 0; k < nodeNum; k++) { if (Edge[j][k] == 1 && flag[k] == false) { flag[k] = true; System.out.print(Vnode[k] + " "); queue.offer(k); } } } } public static void main(String[] args) { GraphIterateMatrix graphIterateMatrix = new GraphIterateMatrix(); graphIterateMatrix.Dfs(); System.out.println(); graphIterateMatrix.Bfs(); } }
原文地址:http://blog.csdn.net/a2bgeek/article/details/38823351