标签:style name print 情况 uil 试题 stream buffers 成员
[BZOJ1086][SCOI2005]王室联邦
试题描述
输入
输出
输入示例
8 2 1 2 2 3 1 8 8 7 8 6 4 6 6 5
输出示例
3 2 1 1 3 3 3 3 2 2 1 8
数据规模及约定
见“输入”
题解
事实上这题没有无解情况。。。
树上分块可以看看 http://www.cnblogs.com/shenben/p/6368457.html,如果不懂中文可以直接看代码。。。
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cctype>
#include <algorithm>
using namespace std;
const int BufferSize = 1 << 16;
char buffer[BufferSize], *Head, *Tail;
inline char Getchar() {
if(Head == Tail) {
int l = fread(buffer, 1, BufferSize, stdin);
Tail = (Head = buffer) + l;
}
return *Head++;
}
int read() {
int x = 0, f = 1; char c = Getchar();
while(!isdigit(c)){ if(c == ‘-‘) f = -1; c = Getchar(); }
while(isdigit(c)){ x = x * 10 + c - ‘0‘; c = Getchar(); }
return x * f;
}
#define maxn 1010
#define maxm 2010
#define maxbl 1010
int n, B, m, head[maxn], nxt[maxm], to[maxm];
void AddEdge(int a, int b) {
to[++m] = b; nxt[m] = head[a]; head[a] = m;
swap(a, b);
to[++m] = b; nxt[m] = head[a]; head[a] = m;
return ;
}
int S[maxn], top, blid[maxn], cb, rt[maxbl];
void build(int u, int fa) {
int bot = top;
for(int e = head[u]; e; e = nxt[e]) if(to[e] != fa) {
build(to[e], u);
if(top - bot >= B) {
rt[++cb] = u;
while(top > bot) blid[S[top--]] = cb;
}
}
S[++top] = u;
return ;
}
int main() {
n = read(); B = read();
for(int i = 1; i < n; i++) {
int a = read(), b = read();
AddEdge(a, b);
}
build(1, 0);
while(top) blid[S[top--]] = cb;
printf("%d\n", cb);
for(int i = 1; i <= n; i++) printf("%d%c", blid[i], i < n ? ‘ ‘ : ‘\n‘);
for(int i = 1; i <= cb; i++) printf("%d%c", rt[i], i < n ? ‘ ‘ : ‘\n‘);
return 0;
}
标签:style name print 情况 uil 试题 stream buffers 成员
原文地址:http://www.cnblogs.com/xiao-ju-ruo-xjr/p/6791421.html