标签:style name print 情况 uil 试题 stream buffers 成员
[BZOJ1086][SCOI2005]王室联邦
试题描述
输入
输出
输入示例
8 2 1 2 2 3 1 8 8 7 8 6 4 6 6 5
输出示例
3 2 1 1 3 3 3 3 2 2 1 8
数据规模及约定
见“输入”
题解
事实上这题没有无解情况。。。
树上分块可以看看 http://www.cnblogs.com/shenben/p/6368457.html,如果不懂中文可以直接看代码。。。
#include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cctype> #include <algorithm> using namespace std; const int BufferSize = 1 << 16; char buffer[BufferSize], *Head, *Tail; inline char Getchar() { if(Head == Tail) { int l = fread(buffer, 1, BufferSize, stdin); Tail = (Head = buffer) + l; } return *Head++; } int read() { int x = 0, f = 1; char c = Getchar(); while(!isdigit(c)){ if(c == ‘-‘) f = -1; c = Getchar(); } while(isdigit(c)){ x = x * 10 + c - ‘0‘; c = Getchar(); } return x * f; } #define maxn 1010 #define maxm 2010 #define maxbl 1010 int n, B, m, head[maxn], nxt[maxm], to[maxm]; void AddEdge(int a, int b) { to[++m] = b; nxt[m] = head[a]; head[a] = m; swap(a, b); to[++m] = b; nxt[m] = head[a]; head[a] = m; return ; } int S[maxn], top, blid[maxn], cb, rt[maxbl]; void build(int u, int fa) { int bot = top; for(int e = head[u]; e; e = nxt[e]) if(to[e] != fa) { build(to[e], u); if(top - bot >= B) { rt[++cb] = u; while(top > bot) blid[S[top--]] = cb; } } S[++top] = u; return ; } int main() { n = read(); B = read(); for(int i = 1; i < n; i++) { int a = read(), b = read(); AddEdge(a, b); } build(1, 0); while(top) blid[S[top--]] = cb; printf("%d\n", cb); for(int i = 1; i <= n; i++) printf("%d%c", blid[i], i < n ? ‘ ‘ : ‘\n‘); for(int i = 1; i <= cb; i++) printf("%d%c", rt[i], i < n ? ‘ ‘ : ‘\n‘); return 0; }
标签:style name print 情况 uil 试题 stream buffers 成员
原文地址:http://www.cnblogs.com/xiao-ju-ruo-xjr/p/6791421.html