标签:des style blog http color java os io strong
#include <iostream> #include<stdio.h> #include<string.h> using namespace std; int n,m; int r[4][2]= {{0,-1},{1,0},{0,1},{-1,0}}; int l[4][2]= {{0,1},{1,0},{0,-1},{-1,0}}; int vis[50][50]; char map[50][50]; int x1,x2,y1,y2,ans; int que[2500][2]; int dfsl(int x,int y,int num1) { if(x==x2&&y==y2) return ++num1; if(x<0||x>=n||y<0||y>=m||map[x][y]==‘#‘) return 0; ans=(ans+3)%4; int temp=0; while(1) { temp=dfsl(x+l[ans][0],y+l[ans][1],num1+1); if(temp>0) break; ans=(ans+1)%4; } return temp; } int dfsr(int x,int y,int num2) { if(x==x2&&y==y2) return ++num2; if(x<0||x>n||y<0||y>m||map[x][y]==‘#‘) return 0; ans=(ans+3)%4; int temp=0; while(1) { temp=dfsr(x+r[ans][0],y+r[ans][1],num2+1); if(temp>0) break; ans=(ans+1)%4; } return temp; } int bfs() { int fir=0,sec=0; que[sec][0]=x1; que[sec++][1]=y1; vis[x1][y1]=1; int step=1; while(fir<sec&&!vis[x2][y2]) { int tmp=sec; step++; while(fir<tmp&&!vis[x2][y2]) { int x=que[fir][0]; int y=que[fir++][1]; for(int i=0; i<4; i++) { int x1=x+r[i][0]; int y1=y+r[i][1]; if(x1>=0&&x1<n&&y1>=0&&y1<m&&!vis[x1][y1]&&map[x1][y1]!=‘#‘) { que[sec][0]=x1; que[sec++][1]=y1; vis[x1][y1]=1; } } } } return step; } int main() { int T; scanf("%d",&T); while(T--) { scanf("%d%d",&m,&n); memset(que,0,sizeof(que)); memset(vis,0,sizeof(vis)); for(int i=0; i<n; i++) { // scanf("%s",map[i]); for(int j=0; j<m; j++) { cin>>map[i][j]; if(map[i][j]==‘S‘) { x1=i; y1=j; } if(map[i][j]==‘E‘) { x2=i; y2=j; } } } ans=0; printf("%d",dfsl(x1,y1,0)); ans=0; printf(" %d",dfsr(x1,y1,0)); printf(" %d\n",bfs()); } return 0; }
Time Limit: 1000 MS Memory Limit: 65536 KB
64-bit integer IO format: %I64d , %I64u Java class name: Main
2 8 8 ######## #......# #.####.# #.####.# #.####.# #.####.# #...#..# #S#E#### 9 5 ######### #.#.#.#.# S.......E #.#.#.#.# #########
37 5 5 17 17 9
题意:
S为起点 E为终点 #不可以走 以左为优先方向 以右为优先方向 最短 的步骤
求最短步骤都要用广搜
标签:des style blog http color java os io strong
原文地址:http://www.cnblogs.com/zhangying/p/3935676.html