标签:omsa gets namespace contest 理解 get ack void return
题目链接 Lomsat gelral
占坑……等深入理解了再来补题解……
1 #include <bits/stdc++.h> 2 3 using namespace std; 4 5 #define rep(i, a, b) for (int i(a); i <= (b); ++i) 6 7 typedef long long LL; 8 9 const int N = 600010; 10 11 int n; 12 int cc[N], col[N], sz[N], son[N]; 13 LL ans[N]; 14 15 vector <int> v[N]; 16 17 void getsize(int x, int fa){ 18 sz[x] = 1; 19 for (auto u : v[x]){ 20 if (u == fa) continue; 21 getsize(u, x); sz[x] += sz[u]; 22 if (!son[x] || sz[u] > sz[son[x]]) son[x] = u; 23 } 24 } 25 26 bool skip[N]; 27 LL sum = 0; 28 int cx = 0; 29 int x, y; 30 31 void edt(int x, int fa, int k){ 32 cc[col[x]] += k; 33 if (k > 0 && cc[col[x]] >= cx){ 34 if (cc[col[x]] > cx) 35 sum = 0, cx = cc[col[x]]; 36 sum += col[x]; 37 } 38 39 for (auto u : v[x]){ 40 if (u == fa || skip[u]) continue; 41 edt(u, x, k); 42 } 43 44 } 45 46 void dfs(int x, int fa, int kep = 0){ 47 for (auto u : v[x]){ 48 if (u == fa || u == son[x]) continue; 49 dfs(u, x, 0); 50 } 51 52 if (son[x]) dfs(son[x], x, 1), skip[son[x]] = 1; 53 edt(x, fa, 1); 54 55 ans[x] = sum; 56 if (son[x]) skip[son[x]] = 0; 57 if (!kep) edt(x, fa, -1), cx = sum = 0; 58 } 59 60 int main(){ 61 62 scanf("%d", &n); 63 rep(i, 1, n) scanf("%d", col + i); 64 65 rep(i, 1, n - 1){ 66 scanf("%d%d", &x, &y); 67 v[x].push_back(y); 68 v[y].push_back(x); 69 } 70 71 getsize(1, 0); 72 dfs(1, 0, 0); 73 74 rep(i, 1, n) printf("%lld\n", ans[i]); 75 return 0; 76 }
Codeforces 600E Lomsat gelral (Dsu On the Tree)
标签:omsa gets namespace contest 理解 get ack void return
原文地址:http://www.cnblogs.com/cxhscst2/p/6798639.html