day1作业二：多级菜单

#定义一个三级菜单字典
dic = {"河南":{"南阳":["邓州市","镇平县","西峡县","新野县","唐河县"],
               "洛阳":["涧西区","西工区","偃师市","孟津县"],
               "周口":["川汇区","西华县","商水县","淮阳县"],
               "开封":["龙亭区","顺河区","鼓楼区","祥符区"],
             },
        "湖南":{"长沙":["芙蓉区","岳麓区","天心区","长沙县"],
                "益阳":["资阳区","赫山区","沅江市","安化县"]
               },
        "广东":{"深圳":["罗湖区","福田区","宝安区","盐田区","龙岗区"],
                "广州":["天河区","越秀区","白云区","黄埔区","番禺区"],
               }
       }

active = True    #设置一个标识符，用于用户输入"q"时退出整个循环

d1 = {}
#设置一个空字典用来存放”省“
for index,province in enumerate(dic.keys(),1):
    d1[index] = province
    print("地区编号:%s       地区名称:%s" %(index,province))
while active:
    #整个程序的循环，默认一直执行
    num1 = input("请输入要查询省的编号(q为退出)：")
    #让用户输入要查询的省的编号
    if num1 == "q":
        #如果用户输入"q"则退出循环
        active = False
    elif int(num1)>len(d1) or int(num1) < 1:
        #如果用户输入的数字不在编码里面，则提示用户重新输入
        print("你输入的编号不对,请重新核对后输入")
    else:
        #如果用户输入正确，则打印相应的省，要使用用户输入的编号，因为我们对比的时候用的就是用户输入的编号
        print(d1[int(num1)])

    d2 = {}
    #定义一个空字典，用于存放市
    for index1,city in enumerate(dic[d1[int(num1)]],1):
        d2[index1] = city
        print("城市编号:%s       城市名称:%s" %(index1,city))
    while active:
        #循环，input()函数要放在循环里面，这样循环的时候才能交互让用户一直输入
        num2 = input("请输入你要查询的城市编号(q为退出或b为返回上一层):")
        if num2 == "q":
            active = False
        elif num2 == "b":
            break
        elif int(num2)>len(d1) or int(num2) < 1:
            print("你输入的查询编号不对，请核对后重新输入......")
        else:
            #打印省市
            print(d1[int(num1)],"     ",d2[int(num2)])
        # while active:
        #while active:
        l1 = dic[d1[int(num1)]][d2[int(num2)]]
        #定义一个列表，用户存放省市下面的县，是一个列表
        while active:
            for i in range(1,len(l1)+1):
                print("市区编号:%s       市区名称:%s" %(i,l1[i-1]))
            num3 = input("请输入您要查询的市区编号：")
            if num3 == "q":
                #active用来退出整个循环，退出程序
                active = False
            elif num3 == ‘b‘:
                #break用来退出当前存放
                break
            elif int(num3) > len(l1) or int(num3) < 1:
                print("你输入的查询编号不对，请核对后重新输入...")
            else:
                print(d1[int(num1)],"     ",d2[int(num2)],"     ",l1[int(num3)-1])