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3. Longest Substring Without Repeating Characters

时间:2017-05-12 14:26:28      阅读:102      评论:0      收藏:0      [点我收藏+]

标签:solution   turn   cte   hashmap   mat   ++   bre   repeat   sub   

Given a string, find the length of the longest substring without repeating characters.

Examples:

Given "abcabcbb", the answer is "abc", which the length is 3.

Given "bbbbb", the answer is "b", with the length of 1.

Given "pwwkew", the answer is "wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.

 

 

public class Solution {
public int lengthOfLongestSubstring(String s) {
if (s.length() == 0) {
return 0;
}

Map<Character, Integer> ht = new HashMap<>();

int count = 0;
int max = 0;
int start = 0;
int end = 0;
while (end < s.length()) {
while (end < s.length() && !ht.containsKey(s.charAt(end))) {
ht.put(s.charAt(end), end);
end++;
count++;
}

max = Math.max(max, count);

if (end >= s.length()) {
break;
}

int mid = ht.get(s.charAt(end));

for (int i = start; i <=mid; i++) {
ht.remove(s.charAt(i));
}
start = mid + 1;
ht.put(s.charAt(end), end);
count = ht.size();
end++;

}

return Math.max(max, count);
}
}

3. Longest Substring Without Repeating Characters

标签:solution   turn   cte   hashmap   mat   ++   bre   repeat   sub   

原文地址:http://www.cnblogs.com/abaoguoguo/p/6845329.html

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