标签:solution turn cte hashmap mat ++ bre repeat sub
Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb", the answer is "abc", which the length is 3.
Given "bbbbb", the answer is "b", with the length of 1.
Given "pwwkew", the answer is "wke", with the length of 3. Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
public class Solution {
public int lengthOfLongestSubstring(String s) {
if (s.length() == 0) {
return 0;
}
Map<Character, Integer> ht = new HashMap<>();
int count = 0;
int max = 0;
int start = 0;
int end = 0;
while (end < s.length()) {
while (end < s.length() && !ht.containsKey(s.charAt(end))) {
ht.put(s.charAt(end), end);
end++;
count++;
}
max = Math.max(max, count);
if (end >= s.length()) {
break;
}
int mid = ht.get(s.charAt(end));
for (int i = start; i <=mid; i++) {
ht.remove(s.charAt(i));
}
start = mid + 1;
ht.put(s.charAt(end), end);
count = ht.size();
end++;
}
return Math.max(max, count);
}
}
3. Longest Substring Without Repeating Characters
标签:solution turn cte hashmap mat ++ bre repeat sub
原文地址:http://www.cnblogs.com/abaoguoguo/p/6845329.html