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CodeForces 279B Books (滑动窗口)

时间:2017-05-12 23:52:18      阅读:263      评论:0      收藏:0      [点我收藏+]

标签:print   vector   mat   ++i   1.0   book   多少   sign   open   

题意:给定n本书的阅读时间,然后你从第 i 本开始阅读,问你最多能看多少本书在给定时间内。

析:就是一个滑动窗口的水题。

代码如下:

#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <cstdio>
#include <string>
#include <cstdlib>
#include <cmath>
#include <iostream>
#include <cstring>
#include <set>
#include <queue>
#include <algorithm>
#include <vector>
#include <map>
#include <cctype>
#include <cmath>
#include <stack>
#include <sstream>
#define debug() puts("++++");
#define gcd(a, b) __gcd(a, b)
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define freopenr freopen("in.txt", "r", stdin)
#define freopenw freopen("out.txt", "w", stdout)
using namespace std;

typedef long long LL;
typedef unsigned long long ULL;
typedef pair<int, int> P;
const int INF = 0x3f3f3f3f;
const LL LNF = 1e16;
const double inf = 0x3f3f3f3f3f3f;
const double PI = acos(-1.0);
const double eps = 1e-8;
const int maxn = 1e5 + 10;
const int mod = 1e9 + 7;
const int dr[] = {-1, 0, 1, 0};
const int dc[] = {0, 1, 0, -1};
const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"};
int n, m;
const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
inline bool is_in(int r, int c){
  return r >= 0 && r < n && c >= 0 && c < m;
}
int a[maxn];

int main(){
  scanf("%d %d", &n, &m);
  int ans = 0;
  int i = 0, j = 0, sum = 0;
  while(j < n){
    scanf("%d", a + j);
    sum += a[j];
    if(sum <= m)  ans = max(ans, j-i+1);
    else  while(sum > m)  sum -= a[i], ++i;
    ++j;
  }
  printf("%d\n", ans);
  return 0;
}

  

CodeForces 279B Books (滑动窗口)

标签:print   vector   mat   ++i   1.0   book   多少   sign   open   

原文地址:http://www.cnblogs.com/dwtfukgv/p/6847641.html

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