标签:字符串 字符 new paper mono otto not char title
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg", "add",
return true.
Given "foo", "bar",
return false.
Given "paper", "title",
return true.
Note:
You may assume both s and t have the same length.
两字符串有映射关系,即一一相应关系。
如egg,add.
e和a相应,g和d相应
刚開始用的map
class Solution {
public:
bool isIsomorphic(string s, string t) {
int n =s.length();
map<int,int>m1,m2;
for (int i = 0;i < n;i++) {
m1[s[i]] = t[i];
m2[t[i]] = s[i];
}
for (int i = 0;i < n;i++) {
if (m1[s[i]] != t[i]) return false;
if (m2[t[i]] != s[i]) return false;
}
return true;
}
};class Solution {
public:
bool isIsomorphic(string s, string t) {
int n =s.length();
int m1[130] = {0},m2[130] = {0};
for (int i = 0;i < n;i++) {
m1[s[i]] = t[i];
m2[t[i]] = s[i];
}
for (int i = 0;i < n;i++) {
if (m1[s[i]] != t[i]) return false;
if (m2[t[i]] != s[i]) return false;
}
return true;
}
};
leetcode-205-Isomorphic Strings
标签:字符串 字符 new paper mono otto not char title
原文地址:http://www.cnblogs.com/wzzkaifa/p/6849998.html