标签：style blog color io strong for ar div log
Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
思路：
1 class Solution { 2 public: 3 int lengthOfLastWord( const char *s ) { 4 int ret = 0, prev = -1, i = 0; 5 while( s[i] != ‘\0‘ ) { 6 if( s[i] == ‘ ‘ ) { 7 if( i - prev - 1 > 0 ) { ret = i - prev - 1; } 8 prev = i; 9 } 10 ++i; 11 } 12 if( i - prev - 1 > 0 ) { ret = i - prev - 1; } 13 return ret; 14 } 15 };
标签：style blog color io strong for ar div log
原文地址：http://www.cnblogs.com/moderate-fish/p/3937791.html
