标签:air void sub bool ati == code value highlight
二分。
如果$n≤m$,显然只能$n$天。
如果$n>m$,至少可以$m$天,剩余还可以支撑多少天,可以二分计算得到,也可以推公式。二分计算的话可能爆$long$ $long$,上了个$Java$。
import java.math.BigInteger; import java.util.Scanner; public class Main { static Scanner cin = new Scanner(System.in); static BigInteger sum(BigInteger L,BigInteger R) { if(L.compareTo(R)>0) return BigInteger.ZERO; BigInteger A = L.add(R); BigInteger B = R.subtract(L); B = B.add(BigInteger.ONE); BigInteger c = A.multiply(B); return c.divide(BigInteger.valueOf(2)); } public static void main(String []args) { BigInteger m,n; n = cin.nextBigInteger(); m = cin.nextBigInteger(); if(n.compareTo(m)<=0) { System.out.println(n); } else { BigInteger ans = m; BigInteger sy = n.subtract(m); BigInteger hai = BigInteger.ZERO; BigInteger L = BigInteger.ZERO, R = sy; boolean pp=false; while(L.compareTo(R)<=0) { BigInteger mid = (L.add(R).divide(BigInteger.valueOf(2))); if(sum(ans.add(BigInteger.ONE),ans.add(mid)).compareTo(sy.add(m.multiply(mid)))<0) { pp=true; hai = mid; L = mid.add(BigInteger.ONE); } else if(sum(ans.add(BigInteger.ONE),ans.add(mid)).compareTo(sy.add(m.multiply(mid)))==0) { pp=false; hai = mid; L = mid.add(BigInteger.ONE); } else R = mid.subtract(BigInteger.ONE); } ans = ans.add(hai); if(pp == true) ans = ans.add(BigInteger.ONE); System.out.println(ans); } } }
CodeForces 785C Anton and Fairy Tale
标签:air void sub bool ati == code value highlight
原文地址:http://www.cnblogs.com/zufezzt/p/6868950.html