码迷,mamicode.com
首页 > 其他好文 > 详细

Codeforces Round #263 (Div. 2) proC

时间:2014-08-27 09:29:07      阅读:211      评论:0      收藏:0      [点我收藏+]

标签:acm   algorithm   算法   codeforces   递归   

题目:

C. Appleman and Toastman
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Appleman and Toastman play a game. Initially Appleman gives one group of n numbers to the Toastman, then they start to complete the following tasks:

  • Each time Toastman gets a group of numbers, he sums up all the numbers and adds this sum to the score. Then he gives the group to the Appleman.
  • Each time Appleman gets a group consisting of a single number, he throws this group out. Each time Appleman gets a group consisting of more than one number, he splits the group into two non-empty groups (he can do it in any way) and gives each of them to Toastman.

After guys complete all the tasks they look at the score value. What is the maximum possible value of score they can get?

Input

The first line contains a single integer n (1?≤?n?≤?3·105). The second line contains n integers a1a2, ..., an (1?≤?ai?≤?106) — the initial group that is given to Toastman.

Output

Print a single integer — the largest possible score.

Sample test(s)
input
3
3 1 5
output
26
input
1
10
output
10
Note

Consider the following situation in the first example. Initially Toastman gets group [3, 1, 5] and adds 9 to the score, then he give the group to Appleman. Appleman splits group [3, 1, 5] into two groups: [3, 5] and [1]. Both of them should be given to Toastman. When Toastman receives group [1], he adds 1 to score and gives the group to Appleman (he will throw it out). When Toastman receives group [3, 5], he adds 8 to the score and gives the group to Appleman. Appleman splits [3, 5] in the only possible way: [5] and [3]. Then he gives both groups to Toastman. When Toastman receives [5], he adds 5 to the score and gives the group to Appleman (he will throws it out). When Toastman receives [3], he adds 3 to the score and gives the group to Appleman (he will throws it out). Finally Toastman have added 9 + 1 + 8 + 5 + 3 = 26 to the score. This is the optimal sequence of actions.


题意分析:

题意还是比较明白。
对原数组进行排序,然后一个递归模拟一下就行了。

代码:

#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <string>
#include <iostream>


using namespace std;


long long a[300005];
int main()
{
    int n;
    long long ans;
    while(scanf("%d",&n)!=EOF)
    {
        ans=0;
        for(int i=1;i<=n;i++)
        {
            cin>>a[i];
        }
        sort(a+1,a+n+1);
        for(int i=1;i<=n;i++)
        {
            a[i]+=a[i-1];
        }
        ans=a[n];
        for(int i=0;i<=n-2;i++)
        {
            ans+=(a[n]-a[i]);
        }
        cout<<ans<<endl;
    }
}


Codeforces Round #263 (Div. 2) proC

标签:acm   algorithm   算法   codeforces   递归   

原文地址:http://blog.csdn.net/notdeep__acm/article/details/38858993

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!