标签:time end span last uil integer nbsp get 相关
Date(...), DateTime(...), RelativeDate(...), Year(...), Month(...), Day(...), DaysAfter(...)
//==================================================================== // 事件: uf_get_first_day() //-------------------------------------------------------------------- // 描述: 根据日期获取间隔n月第一天 //-------------------------------------------------------------------- // 参数: // value date ad_date // value integer ai_n //-------------------------------------------------------------------- // 返回: date //==================================================================== Date ld_first_day Int li_year, li_month li_year = Year(ad_date) li_month = Month(ad_date) li_month = li_month + ai_n Do While li_month < 0 li_month = li_month + 12 li_year = li_year - 1 Loop Do While li_month > 12 li_month = li_month - 12 li_year = li_year + 1 Loop ld_first_day = Date(String(li_year) + ‘-‘ + String(li_month) + ‘-1‘) Return ld_first_day
//==================================================================== // 事件: uf_get_last_day() //-------------------------------------------------------------------- // 描述: 根据日期获取当月最后一天的日期 //-------------------------------------------------------------------- // 参数: // value date ad_date //-------------------------------------------------------------------- // 返回: date //==================================================================== Date ld_last_day Int li_year, li_month, li_day li_year = Year(ad_date) li_month = Month(ad_date) li_day = uf_get_daynum(ad_date) ld_last_day = Date(String(li_year) + ‘-‘ + String(li_month) + ‘-‘ + String(li_day)) Return ld_last_day
//==================================================================== // 事件: u_sysfunc.uf_get_daynum() //-------------------------------------------------------------------- // 描述: 根据日期获取当月的天数 //-------------------------------------------------------------------- // 参数: // value date ad_date //-------------------------------------------------------------------- // 返回: integer //==================================================================== Int li_year, li_month, li_daynum li_year = Year(ad_date) li_month = Month(ad_date) Choose Case li_month Case 1, 3, 5, 7, 8, 10, 12 li_daynum = 31 Case 4, 6, 9, 11 li_daynum = 30 Case 2 If (Mod(li_year, 4) = 0 And Mod(li_year, 100) <> 0) Or Mod(li_year, 400) = 0 Then li_daynum = 29 Else li_daynum = 28 End If End Choose Return li_daynum
标签:time end span last uil integer nbsp get 相关
原文地址:http://www.cnblogs.com/yarightok/p/6877782.html