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178. Rank Scores (Medium)

时间:2017-05-21 14:44:51      阅读:189      评论:0      收藏:0      [点我收藏+]

标签:where   rank   integer   sel   3.5   log   ber   repo   code   

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.

+----+-------+
| Id | Score |
+----+-------+
| 1 | 3.50 |
| 2 | 3.65 |
| 3 | 4.00 |
| 4 | 3.85 |
| 5 | 4.00 |
| 6 | 3.65 |
+----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

+-------+------+
| Score | Rank |
+-------+------+
| 4.00 | 1 |
| 4.00 | 1 |
| 3.85 | 2 |
| 3.65 | 3 |
| 3.65 | 3 |
| 3.50 | 4 |
+-------+------+

 

Solution:

SELECT T2.Score AS Score, (
    SELECT COUNT(*) + 1
    FROM (SELECT T1.Score FROM Scores T1 GROUP BY Score ORDER BY Score DESC) TEMP
    WHERE T2.Score < TEMP.Score
    ) AS Rank
FROM Scores T2
ORDER BY Score DESC

178. Rank Scores (Medium)

标签:where   rank   integer   sel   3.5   log   ber   repo   code   

原文地址:http://www.cnblogs.com/sixu/p/6884754.html

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