标签：ber for out esc base which target call one
https://leetcode.com/problems/first-bad-version/#/description
You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.
Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.
You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.
Sol 1:
Binary search
class Solution(object): def firstBadVersion(self, n): """ :type n: int :rtype: int """ if isBadVersion(1): return 1 l = 1 r = n while l < r - 1: mid = (l+r)/2 if isBadVersion(mid): r = mid else: l = mid return r
Sol 2:
Recursion
class Solution(object): def rec(self,l,r): if(l>r): return 0 else: mid=(l+r)/2 if(isBadVersion(mid)): if(l==r): return l else: return self.rec(l,mid) else: return self.rec(mid+1,r) def firstBadVersion(self, n): """ :type n: int :rtype: int """ ans=self.rec(1,n) return ans
标签：ber for out esc base which target call one
原文地址：http://www.cnblogs.com/prmlab/p/6900677.html
