Hihocode 1304

 1 //最初的梦想，紧握手上
 2 
 3 
 4 #include <stdio.h>
 5 #include <string.h>
 6 #include <math.h>
 7 #define eps 1e-5
 8 bool used[4];
 9 int num[4];
10 int nownum[4];
11 int ope[3];
12 double judge(double a,double b,int x)    //运算符
13 {
14     switch (x)
15     {
16          case 1:
17             return a+b;
18         case 2:
19             return a-b;
20         case 3:
21             return a*b;
22         case 4:
23             if(fabs(b-0)>eps)
24                 return a/b;
25             else
26                 return -999999;
27         case 5:
28             return b-a;
29         case 6:
30             if(fabs(a-0)>eps)
31                 return b/a;
32             else return -999999;
33     }
34 
35 }
36 double jud1()  //第一种判断
37 {
38     return judge(judge(judge(nownum[0],nownum[1],ope[0]),nownum[2],ope[1]),nownum[3],ope[2]);
39 
40 }
41 
42 double jud2()  //第二种判断
43 {
44     return judge(judge(nownum[0],nownum[1],ope[0]),judge(nownum[2],nownum[3],ope[1]),ope[2]);
45 }
46 bool calc(int deep)    //枚举运算符
47 {
48     if(deep>2)
49     {
50         if(fabs(jud1()-24)<eps)
51             return true;
52         if(fabs(jud2()-24)<eps)
53             return true;
54         return false;
55     }
56     for(int i =1; i<=6; i++)
57     {
58         ope[deep] = i;
59         if(calc(deep+1))
60             return true;
61     }
62     return false;
63 }
64 
65 bool dfs(int deep)    //枚举数字
66 {
67     if(deep>3)
68         return calc(0);
69     for(int i = 0; i<4; i++)
70         if(used[i])
71         {
72             used[i] = false;
73             nownum[deep] = num[i];
74             if(dfs(deep+1))
75                 return true;
76             used[i] = true;
77         }
78     return false;
79 }
80 
81 
82 int main()
83 {
84    // freopen("in.txt","r",stdin);
85     int a,b,c,d;
86     int t;
87     scanf("%d",&t);
88     while(t--)
89     {
90         memset(used,true,sizeof(used));
91         scanf("%d%d%d%d",&num[0],&num[1],&num[2],&num[3]);
92         if(dfs(0))
93             printf("Yes\n");
94         else
95             printf("No\n");
96     }
97     return 0;
98 }