标签:segment 汇编 ace stack modify mod push replace tar
2、编程,完成7.9中的程序
assume cs:codesg,ds:datasg,ss:stacksg stacksg segment dw 0,0,0,0,0,0,0,0 stacksg ends datasg segment db ‘1. display ‘ db ‘2. brows ‘ db ‘3. replace ‘ db ‘4. modify ‘ datasg ends codesg segment start: mov ax,datasg mov ds,ax mov si,0 mov cx,4 s0: push cx mov bx,0 mov cx,4 s1: mov al,[bx][si].3 and al,11011111B mov [bx][si].3,al add bx,10h loop s1 inc si pop cx loop s0 mov ax,4c00h int 21h codesg ends end start
标签:segment 汇编 ace stack modify mod push replace tar
原文地址:http://www.cnblogs.com/Since-natural-ran/p/6928076.html