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38. Count and Say - Unsolved

时间:2017-06-06 22:01:16      阅读:142      评论:0      收藏:0      [点我收藏+]

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https://leetcode.com/problems/count-and-say/#/description

 

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

 

Sol:

 

class Solution(object):
    def countAndSay(self, n):
        """
        :type n: int
        :rtype: str
        """
        s=1
        for i in range(n-1):
            count = 1
            temp = []
            for index in range(1,len(s)):
                if s[index] == s[index-1]:
                    count += 1
                else:
                    temp.append(str(count))
                    temp.append(s[index-1])
                    count = 1
            temp.append(str(count))
            temp.append(s[-1])
            s = ‘‘.join(temp)
        return s

 

TWO SOLUTIONS IN:

https://discuss.leetcode.com/topic/28084/simple-python-solution/4

 

.join() in python 

http://www.cnblogs.com/jsplyy/p/5634640.html

 

 

 

38. Count and Say - Unsolved

标签:tps   app   html   type   strong   log   and   ==   read   

原文地址:http://www.cnblogs.com/prmlab/p/6953402.html

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