码迷,mamicode.com
首页 > 其他好文 > 详细

Recover Binary Search Tree

时间:2014-08-28 19:33:55      阅读:266      评论:0      收藏:0      [点我收藏+]

标签:style   blog   http   color   io   strong   ar   for   div   

Two elements of a binary search tree (BST) are swapped by mistake.

Recover the tree without changing its structure.

Note:
A solution using O(n) space is pretty straight forward. Could you devise a constant space solution?

 

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

 

中序遍历整棵树,bst的节点值则是有序的,如果发现前驱节点值大于当前节点值,那么就是异常情况

异常情况有两种,一种是前后相连的节点,另一种是不相连的节点,代码如下:

 1 /**
 2  * Definition for binary tree
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     void recoverTree(TreeNode *root) {
13         if( !root ) return ;
14         stack<TreeNode*> st;
15         TreeNode* cur = root;
16         while( cur ) {
17             st.push(cur);
18             cur = cur->left;
19         }
20         TreeNode* pre = 0;
21         TreeNode* fnode = 0;
22         TreeNode* snode = 0;
23         while( !st.empty() ) {
24             cur = st.top();
25             st.pop();
26             if( pre && pre->val > cur->val ) {  //前驱值大于当前节点值时则为异常情况
27                 if( !fnode ) fnode = pre, snode = cur;  //可能出现出错的两个节点刚好是前后连续的
28                 else {
29                     snode = cur;    //再次找到前驱值大于当前节点值,那么他们就不是相连的
30                     break;
31                 }
32             }
33             pre = cur;
34             cur = cur->right;
35             while( cur ) {
36                 st.push(cur);
37                 cur = cur->left;
38             }
39         }
40         swap(fnode->val, snode->val);   //交换两节点的值
41     }
42 };

 

Recover Binary Search Tree

标签:style   blog   http   color   io   strong   ar   for   div   

原文地址:http://www.cnblogs.com/bugfly/p/3942200.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!