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hadoop 2.6.0 LightWeightGSet源码分析

时间:2017-06-11 21:43:36      阅读:237      评论:0      收藏:0      [点我收藏+]

标签:方法   move   trie   ado   math类   arc   elements   current   remove   

LightWeightGSet的作用用一个数组来存储元素,而且用链表来解决冲突。不能rehash。所以内部数组永远不用改变大小。此类不支持空元素。

此类也不是线程安全的。有两个类型參数。第一个用于查找元素,第二个类型參数必须是第一个类型參数的子类,而且必须实现LinkedElement接口。

/**
 * A low memory footprint {@link GSet} implementation,
 * which uses an array for storing the elements
 * and linked lists for collision resolution.
 *
 * No rehash will be performed.
 * Therefore, the internal array will never be resized.
 *
 * This class does not support null element.
 *
 * This class is not thread safe.
 *
 * @param <K> Key type for looking up the elements
 * @param <E> Element type, which must be
 *       (1) a subclass of K, and
 *       (2) implementing {@link LinkedElement} interface.
 */


里面各组件都很好理解,唯一不好理解的是Iterator,

public class SetIterator implements Iterator<E> {
    /** The starting modification for fail-fast. */
    private int iterModification = modification;
    /** The current index of the entry array. */
    private int index = -1;
    private LinkedElement cur = null;//
    private LinkedElement next = nextNonemptyEntry();//next总是指向下一个元素,在初始化时就完毕指下第一个元素。

//在调用next()方法之后,next置为空。直到调用 ensureNext()方法。  private boolean trackModification = true; /** Find the next nonempty entry starting at (index + 1). */ private LinkedElement nextNonemptyEntry() { for(index++; index < entries.length && entries[index] == null; index++); return index < entries.length? entries[index]: null; } private void ensureNext() { if (trackModification && modification != iterModification) { throw new ConcurrentModificationException("modification=" + modification + " != iterModification = " + iterModification); } if (next != null) { return; } if (cur == null) { return; } next = cur.getNext(); if (next == null) { next = nextNonemptyEntry(); } } @Override public boolean hasNext() { ensureNext(); return next != null; } @Override public E next() { ensureNext(); if (next == null) { throw new IllegalStateException("There are no more elements"); } cur = next; next = null; return convert(cur); } @SuppressWarnings("unchecked") @Override public void remove() { ensureNext(); if (cur == null) { throw new IllegalStateException("There is no current element " + "to remove"); } LightWeightGSet.this.remove((K)cur); iterModification++; cur = null; } public void setTrackModification(boolean trackModification) { this.trackModification = trackModification; } }</span>



computeCapacity()是一个工具方法,用于一定比例的内存的容器,能够存储多少对象。

參数,第一个是占最大内存的百分比,第二个是名称。没有什么用,仅仅用作日志输出。



/**
   * Let t = percentage of max memory.
   * Let e = round(log_2 t).
   * Then, we choose capacity = 2^e/(size of reference),
   * unless it is outside the close interval [1, 2^30].
   */
  public static int computeCapacity(double percentage, String mapName) {
    return computeCapacity(Runtime.getRuntime().maxMemory(), percentage,
        mapName);
  }
  
  @VisibleForTesting
  static int computeCapacity(long maxMemory, double percentage,
      String mapName) {
    if (percentage > 100.0 || percentage < 0.0) {
      throw new HadoopIllegalArgumentException("Percentage " + percentage
          + " must be greater than or equal to 0 "
          + " and less than or equal to 100");
    }
    if (maxMemory < 0) {
      throw new HadoopIllegalArgumentException("Memory " + maxMemory
          + " must be greater than or equal to 0");
    }
    if (percentage == 0.0 || maxMemory == 0) {
      return 0;
    }
    //VM detection
    //See http://java.sun.com/docs/hotspot/HotSpotFAQ.html#64bit_detection
    final String vmBit = System.getProperty("sun.arch.data.model");

    //Percentage of max memory
    final double percentDivisor = 100.0/percentage;
    final double percentMemory = maxMemory/percentDivisor;
    
    //compute capacity
  /*
  具体描写叙述例如以下:e1应该是以2为base的对数。如percentMemory为1024,结果为10。由于Math类不提供以2为base的对数,
所以採用了间接的方法,先求自然对数,再除以2的自然对数。例System.out.println(Math.log(1024)/Math.log(2));结果为10。
+0.5是为了四舍五入。
假设占用内存为1G,则e1为30.
e2的值,假设系统为32位,则减2,由于2,e2为28,c为2的28次方,为256M个对象,每一个对象指针在32位系统中占4字节。总共1G.
假设系统为64位,e2为27,即对象个数为128M,每一个对象指针为8字节。所以共占1G.
*/ 
 final int e1 = (int)(Math.log(percentMemory)/Math.log(2.0) + 0.5);
    final int e2 = e1 - ("32".equals(vmBit)?

2: 3);     final int exponent = e2 < 0? 0: e2 > 30? 30: e2;     final int c = 1 << exponent;     LOG.info("Computing capacity for map " + mapName);     LOG.info("VM type       = " + vmBit + "-bit");     LOG.info(percentage + "% max memory "         + StringUtils.TraditionalBinaryPrefix.long2String(maxMemory, "B", 1)         + " = "         + StringUtils.TraditionalBinaryPrefix.long2String((long) percentMemory,             "B", 1));     LOG.info("capacity      = 2^" + exponent + " = " + c + " entries");     return c;   }


hadoop 2.6.0 LightWeightGSet源码分析

标签:方法   move   trie   ado   math类   arc   elements   current   remove   

原文地址:http://www.cnblogs.com/cynchanpin/p/6986445.html

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