标签:str class cin upd put i++ color clu ret
思路:
Bellman-Ford判断是否含有经过源点的正权回路。
实现:
1 #include <iostream> 2 #include <cstdio> 3 using namespace std; 4 5 const int MAXN = 105, MAXM = 105; 6 7 int n, m, s; 8 double d, dist[MAXN]; 9 struct edge 10 { 11 int from, to; 12 double c, r; 13 }; 14 edge es[2 * MAXM]; 15 16 bool check(int s, double d) 17 { 18 for (int i = 1; i <= n; i++) dist[i] = 0; 19 dist[s] = d; 20 bool update = true; 21 while (update) 22 { 23 if (dist[s] > d) return true; 24 update = false; 25 for (int i = 1; i <= 2 * m; i++) 26 { 27 edge & e = es[i]; 28 if (dist[e.from] > 0 && dist[e.to] < (dist[e.from] - e.c) * e.r) 29 { 30 dist[e.to] = (dist[e.from] - e.c) * e.r; 31 update = true; 32 } 33 } 34 } 35 return dist[s] > d; 36 } 37 38 int main() 39 { 40 cin >> n >> m >> s >> d; 41 for (int i = 1; i < 2 * m; i += 2) 42 { 43 cin >> es[i].from >> es[i].to >> es[i].r >> es[i].c; 44 cin >> es[i + 1].r >> es[i + 1].c; 45 es[i + 1].from = es[i].to; 46 es[i + 1].to = es[i].from; 47 } 48 if (!check(s, d)) puts("NO"); 49 else puts("YES"); 50 }
标签:str class cin upd put i++ color clu ret
原文地址:http://www.cnblogs.com/wangyiming/p/6994411.html