记录day3

 1 import turtle
 2 
 3 def square(t, length):
 4     for i in range(4):
 5         t.fd(length)
 6         t.lt(90)
 7         
 8 def polygon(turtle, length, numOfSide):
 9     degree = 360 / numOfSide # 根据几边形决定每次转动的角度
10     for i in range(numOfSide):
11         turtle.fd(length)
12         turtle.lt(degree)
13         
14 bob = turtle.Turtle()
15 polygon(turtle = bob, numOfSide = 9, length = 100)
16 turtle.mainloop()

 1 import turtle
 2 
 3 def square(t, length):
 4     for i in range(4):
 5         t.fd(length)
 6         t.lt(90)
 7         
 8 def polygon(turtle, length, numOfSide):
 9     degree = 360 / numOfSide # 根据几边形决定每次转动的角度
10     for i in range(numOfSide):
11         turtle.fd(length)
12         turtle.lt(degree)
13         
14         
15 def circle(turtle, radius):
16     ‘‘‘
17     由于不能精确算出一个半径对应几边形，但是一个基本的逻辑是半径越大，边数也要越大
18     还有一个问题就是，我也无法精确算出每一步到底改走多远，一般来说半径越大，边数越大，移动举例要越小
19     ‘‘‘
20     numOfSide = radius
21     length = 1000 / numOfSide
22     polygon(turtle, length, numOfSide)
23     
24     
25     
26 bob = turtle.Turtle()
27 # polygon(turtle = bob, numOfSide = 9, length = 100)
28 circle(bob, 200)
29 turtle.mainloop()