标签:off code div ++i log name c++ div2 else
题意:给出n个温度区间,k,Q个询问,每个询问给出一个温度区间x--y。问这之间有多少个温度在给出K的温度区间内。
思路:前缀和小技巧
1 #include<bits/stdc++.h> 2 using namespace std; 3 const int N = 3e5+10; 4 5 int n,k,q,x,y,a[N],b[N]; 6 7 int main() { 8 scanf("%d%d%d",&n,&k,&q); 9 for(int i = 1; i <= n; ++i) { 10 scanf("%d%d",&x,&y); 11 b[x] += 1; 12 b[y+1] += -1; 13 } 14 for(int i = 1; i <= 200000; ++i) { 15 b[i] += b[i-1]; 16 if(b[i] >= k) { 17 a[i] = 1; 18 } 19 else { 20 a[i] = 0; 21 } 22 } 23 for(int i = 1; i <= 200000; ++i) a[i] += a[i-1]; 24 for(int i=1;i<=q;i++) { 25 int x,y; 26 scanf("%d%d",&x,&y); 27 cout<<a[y] - a[x-1]<<endl; 28 } 29 return 0; 30 }
#419(div2) B. Karen and Coffee
标签:off code div ++i log name c++ div2 else
原文地址:http://www.cnblogs.com/hhxj/p/7044150.html