标签:style blog color os io ar for div log
假定一副新扑克牌的顺序为:大王、小王、黑桃A,2,3,…,T,J,Q,K、红心A,2,3,…,T,J,Q,K、方块 A,2,3,…,T,J,Q,K、梅花A,2,3,…,T,J,Q,K。现将两副扑克牌摞放在一起,然后将最上面的一张牌舍去,将之后的一张牌移到整副牌 的最下面,重复此过程。问:最后剩下的是哪张牌?
1 #include<iostream> 2 using namespace std; 3 class Sqlist //用循环链表 4 { 5 public: 6 struct Node //定义结构体 7 { 8 char color; 9 int num; 10 Node * next; 11 Node(char a) //构造函数 12 { 13 color = a; 14 next = NULL; 15 } 16 Node() //构造函数 17 { 18 next = NULL; 19 } 20 void init(char a,int b)//赋值函数 21 { 22 color = a; 23 num = b; 24 next=NULL; 25 } 26 }; 27 Node * head;//头指针 28 Node * cur;//当前指针 29 Node * pre;//前驱指针 30 Sqlist()//构造函数 31 { 32 Node * tem = new Node(); 33 Node * tempre = new Node(); 34 head = tem; 35 cur = head; 36 pre = tempre; 37 pre->next = cur; 38 for(int i = 0 ; i < 108 ; i ++) 39 { 40 if(i==0||i==54)//第1张牌和第55张牌 41 { 42 Node * tem = new Node(‘J‘);//大王 43 cur -> next = tem; 44 cur = cur -> next; 45 pre = pre -> next; 46 } 47 if(i==1||i==55)//第二张牌和第56张牌 48 { 49 Node * tem = new Node(‘j‘);//小王 50 cur -> next = tem; 51 cur = cur -> next; 52 pre = pre -> next; 53 } 54 if((i>=2&&i<=14)||(i>=56&&i<=68))//黑桃 55 { 56 Node * tem = new Node(); 57 if(i>=2&&i<=14) tem->init(‘S‘,i-1); 58 if(i>=56&&i<=68)tem->init(‘S‘,i-55); 59 cur -> next = tem; 60 cur = cur -> next; 61 pre = pre -> next; 62 } 63 if((i>=15&&i<=27)||(i>=69&&i<=81))//红桃 64 { 65 Node * tem = new Node();; 66 if(i>=15&&i<=27) tem->init(‘H‘,i-14); 67 if(i>=69&&i<=81)tem->init(‘H‘,i-68); 68 cur -> next = tem; 69 cur = cur -> next; 70 pre = pre -> next; 71 } 72 if((i>=28&&i<=40)||(i>=82&&i<=94))//方片 73 { 74 Node * tem = new Node();; 75 if(i>=28&&i<=40) tem->init(‘D‘,i-27); 76 if(i>=82&&i<=94)tem->init(‘D‘,i-81); 77 cur -> next = tem; 78 cur = cur -> next; 79 pre = pre -> next; 80 } 81 if((i>=41&&i<=53)||(i>=95&&i<=107))//梅花 82 { 83 Node * tem = new Node();; 84 if(i>=41&&i<=53) tem->init(‘C‘,i-40); 85 if(i>=95&&i<=107)tem->init(‘C‘,i-94); 86 cur -> next = tem; 87 cur = cur -> next; 88 pre = pre -> next; 89 } 90 } 91 cur = head -> next; 92 pre = pre -> next; 93 } 94 void print()//两副牌落一块 顺序打印 95 { 96 Node * tem = head; 97 tem = tem -> next; 98 for(int i = 0 ; i < 108 ; i++) 99 { 100 cout<<"i="<<i<<" "<<tem->color<<" "<<tem->num<<endl; 101 tem = tem -> next; 102 } 103 } 104 void out()//出牌(类似约瑟夫环) 105 { 106 for(int i = 0 ; i < 107 ; i ++) 107 { 108 cout<<"out puke is:"<<cur->color<<" "<<cur->num<<endl; 109 pre -> next = cur -> next; 110 pre = pre -> next; 111 cur = cur -> next; 112 cur = cur -> next; 113 } 114 cout<<"Final show:"<<cur->color<<" "<<cur->num; 115 } 116 }; 117 int main() 118 { 119 Sqlist dusk; 120 dusk.print(); 121 dusk.out(); 122 }
标签:style blog color os io ar for div log
原文地址:http://www.cnblogs.com/Duskcl/p/3945847.html