Remove Nth Node From End of List

标签：leetcode

Given a linked list, remove the n^th node from the end of list and return its head.

For example,

   Given linked list: 1->2->3->4->5, and n = 2.

   After removing the second node from the end, the linked list becomes 1->2->3->5.

Note:
Given n will always be valid.
Try to do this in one pass.

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) {
 *         val = x;
 *         next = null;
 *     }
 * }
 */
public class Solution {
    public ListNode removeNthFromEnd(ListNode head, int n) {
    	ListNode left = head;
    	ListNode right = head;
    	for(int i = 0;i<n;i++){
    		right = right.next;
    	}
    	if(right ==null){
    		head = head.next;
    		return head;
    	}
    	while(right.next!=null){
    		left =left.next;
    		right = right.next;
    	}
    	left.next=left.next.next;
    	return head;
    }
}

Remove Nth Node From End of List

标签：leetcode

原文地址：http://blog.csdn.net/guorudi/article/details/38930181