[51nod]1004 n^n的末位数字

#include <iostream>
using namespace std;

#define LL long long
#define Mod 10

LL Pow(LL a, LL n)
{
    int ans = 1;
    while (n) {
        if (n & 1)
            ans = (ans*a)%Mod;
        a = (a*a)%Mod;
        n >>= 1;
    }
    return ans%10;
}

int main()
{
    //freopen("1.txt", "r", stdin);
    int a;
    cin >> a;
    cout << Pow(a, a);

    return 0;
}

#include <iostream>
#include <math.h>
#include <stdio.h>
using namespace std;

int main()
{
    //freopen("1.txt", "r", stdin);
    int n;
    cin >> n;
    int a, b;
    a = n % 10;
    b = n % 4;
    if (b == 0)
        b = 4;
    cout << (int)pow(a, b)%10;

    return 0;
}