标签:des style http color os 使用 io strong ar
题目:
Language:
A Simple Problem with Integers
Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. Input The first line contains two numbers N and Q. 1 ≤ N,Q ≤ 100000. Output You need to answer all Q commands in order. One answer in a line. Sample Input 10 5 1 2 3 4 5 6 7 8 9 10 Q 4 4 Q 1 10 Q 2 4 C 3 6 3 Q 2 4 Sample Output 4 55 9 15 Hint
The sums may exceed the range of 32-bit integers.
Source
POJ Monthly--2007.11.25, Yang Yi
代码:
#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<map> #include<vector> #include<cmath> #include<string> #include<queue> #define eps 1e-9 #define ll long long #define INF 0x3f3f3f3f using namespace std; const int maxn=100000+10; ll col[maxn*4]; ll tree[maxn*4]; int n,m; void push_up(int dex) { tree[dex]=tree[dex<<1]+tree[dex<<1|1]; } void push_down(int cnt,int dex) { if(col[dex]) { col[dex<<1]+=col[dex];//这里要累积起来 col[dex<<1|1]+=col[dex]; tree[dex<<1]+=(cnt-(cnt>>1))*col[dex]; tree[dex<<1|1]+=(cnt>>1)*col[dex]; col[dex]=0; } } void buildtree(int l,int r,int dex) { col[dex]=0; if(l==r) { scanf("%I64d",&tree[dex]); return; } int mid=(l+r)/2; buildtree(l,mid,dex<<1); buildtree(mid+1,r,dex<<1|1); push_up(dex); } void update(int L,int R,int l,int r,int dex,long long val) { if(L<=l&&R>=r) { tree[dex]+=(r-l+1)*val; col[dex]+=val; return; } push_down(r-l+1,dex); int mid=(l+r)/2; if(L<=mid) update(L,R,l,mid,dex<<1,val); if(R>mid) update(L,R,mid+1,r,dex<<1|1,val); push_up(dex); } long long Query(int L,int R,int l,int r,int dex) { if(L<=l&&R>=r) return tree[dex]; push_down(r-l+1,dex); int mid=(l+r)/2; if(R<=mid) return Query(L,R,l,mid,dex<<1); else if(L>mid) return Query(L,R,mid+1,r,dex<<1|1); else return Query(L,R,l,mid,dex<<1)+Query(L,R,mid+1,r,dex<<1|1); } int main() { char str[2]; int u,v; long long w; while(~scanf("%d%d",&n,&m)) { buildtree(1,n,1); while(m--) { scanf("%s",str); if(str[0]=='Q') { scanf("%d%d",&u,&v); printf("%I64d\n",Query(u,v,1,n,1)); } else { scanf("%d%d%I64d",&u,&v,&w); update(u,v,1,n,1,w); } } } return 0; } |
poj3468A Simple Problem with Integers(线段树+成段更新)
标签:des style http color os 使用 io strong ar
原文地址:http://blog.csdn.net/u014303647/article/details/38947559