标签:think res idt math air rom problem rip font
Time Limit: 3000MS | Memory Limit: 65536K | |
Total Submissions: 39658 | Accepted: 16530 |
Description
Input
Output
Sample Input
abcd aaaa ababab .
Sample Output
1 4 3
Hint
Source
KMP算法
设字符串的长度为l,假设l%(l-next[l])=0。该序列为循环序列,循环节长度为l-next[l],答案即为l/(l-next[l]);反之则不为循环序列。答案为1。
#include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<cmath> #include<algorithm> #define F(i,j,n) for(int i=j;i<=n;i++) #define D(i,j,n) for(int i=j;i>=n;i--) #define ll long long #define pa pair<int,int> #define maxn 1000010 #define inf 1000000000 using namespace std; char s[maxn]; int l,nxt[maxn]; inline void getnext() { int i=0,j=-1; nxt[0]=-1; while (i<l) { if (j==-1||s[i]==s[j]) nxt[++i]=++j; else j=nxt[j]; } } int main() { scanf("%s",s); while (s[0]!='.') { l=strlen(s); getnext(); if (l%(l-nxt[l])==0) printf("%d\n",l/(l-nxt[l])); else printf("1\n"); scanf("%s",s); } }
标签:think res idt math air rom problem rip font
原文地址:http://www.cnblogs.com/claireyuancy/p/7079795.html