标签:return ssi 选择 eve ntc interview mini should 一个
Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie. Each child i has a greed factor gi, which is the minimum size of a cookie that the child will be content with; and each cookie j has a size sj. If sj >= gi, we can assign the cookie j to the child i, and the child i will be content. Your goal is to maximize the number of your content children and output the maximum number.
Note:
You may assume the greed factor is always positive.
You cannot assign more than one cookie to one child.
Example 1:
Input: [1,2,3], [1,1] Output: 1 Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3. And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content. You need to output 1.
Example 2:
Input: [1,2], [1,2,3] Output: 2 Explanation: You have 2 children and 3 cookies. The greed factors of 2 children are 1, 2. You have 3 cookies and their sizes are big enough to gratify all of the children, You need to output 2.
思路:
先排序,然后为每一个人选择最小的而且满足要求的饼干,记录位置。
int findContentChildren(vector<int>& g, vector<int>& s) { int people = g.size(),cookie = s.size(); sort(g.begin(), g.end()); sort(s.begin(), s.end()); int content = 0; int curindex = 0;//代表饼干的索引 for (int i = 0; i < people;i++) { for (int j = curindex; j < cookie; j++) { if (s[j]>=g[i]) { content++; curindex = j + 1;//j已经被分出去了 得从下一个开始 break; } } } return content; }
标签:return ssi 选择 eve ntc interview mini should 一个
原文地址:http://www.cnblogs.com/hellowooorld/p/7090717.html