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Codeforces Round #313 A. Currency System in Geraldion

时间:2017-07-03 13:55:20      阅读:144      评论:0      收藏:0      [点我收藏+]

标签:else   pst   number   value   size   lan   lin   res   lock   

Description

A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of each value. Such sum is called unfortunate. Gerald wondered: what is the minimum unfortunate sum?

Input

The first line contains number n (1?≤?n?≤?1000) — the number of values of the banknotes that used in Geraldion.

The second line contains n distinct space-separated numbers a1,?a2,?...,?an (1?≤?ai?≤?106) — the values of the banknotes.

Output

Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print ?-?1.

Sample Input

Input
5
1 2 3 4 5
Output
-1

 

题意:求n个整数不能组成的最小整数,假设都存在,输出-1.

思路:假设n个数中有1,则都能组成,输出-1,否则不能组成的最小整数位1,输出1.

代码:

#include<cstdio>
using namespace std;
int a[1010];
int main()
{
    int n,flag=0;
    while(scanf("%d",&n)!=EOF)
   {

    for(int i=0;i<n;i++)
    scanf("%d",&a[i]);
    for(int i=0;i<n;i++)
    {
        if(a[i]==1)
        {
            flag=1;
            break;
        }
    }
    if(flag)
    printf("-1\n");
    else
        printf("1\n");

   }
    return 0;
}


 

Codeforces Round #313 A. Currency System in Geraldion

标签:else   pst   number   value   size   lan   lin   res   lock   

原文地址:http://www.cnblogs.com/cxchanpin/p/7110437.html

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