标签:time lock spi ref and binary his https com
Invert a binary tree.
4 / 2 7 / \ / 1 3 6 9to
4 / 7 2 / \ / 9 6 3 1Trivia:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
题目标签:Tree
这道题目给了我们一个二叉树,让我们把它反转一下。对于每一个点,它的左边和右边子树需要对调一下。利用postOrder 来遍历树,当走到最低端的时候,点 == null, 返回null, 对于每一个点,把它的left 和right 互换一下。return 这个点。
Java Solution:
Runtime beats 27.97%
完成日期:07/04/2017
关键词:Tree
关键点:把left 和right 互换
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution 11 { 12 public TreeNode invertTree(TreeNode root) 13 { 14 if(root == null) 15 return null; 16 17 // continue children 18 invertTree(root.left); 19 invertTree(root.right); 20 21 // swap left and right 22 TreeNode temp; 23 temp = root.left; 24 root.left = root.right; 25 root.right = temp; 26 27 return root; 28 } 29 }
参考资料:N/A
LeetCode 226. Invert Binary Tree (反转二叉树)
标签:time lock spi ref and binary his https com
原文地址:http://www.cnblogs.com/jimmycheng/p/7119053.html