43. Multiply Strings

class Solution(object):
    def multiply(self, num1, num2):
        """
        :type num1: str
        :type num2: str
        :rtype: str
        """
        
        # The key to this problem is that 1) reverse two strings 2) multiply them by digit 3) Store the result in an arrary rathan carry 4) Get the mode(%) of the array as interset it as a result digit. And the tenth (/10) of the array is the carry.  
        num1 = num1[::-1]
        num2 = num2[::-1]
        # initilize arrary 
        # The max length of the multiple of two numbers is the sum of the length of two numbers. 
        arr = [0] * (len(num1) + len(num2))
        for digit1 in range(len(num1)):
            for digit2 in range(len(num2)):
                arr[digit1 + digit2] += int(num1[digit1]) * int(num2[digit2])
        ans = []
        for i in range(len(arr)):
            digit_ans = arr[i] % 10
            carry_ans = arr[i] /10
            if i < len(arr) - 1:
                arr[i+1] += carry_ans
            # insert the digit of answer at position 0    
            ans.insert(0, str(digit_ans))
        while ans[0] == "0" and len(ans) > 1:
            del ans[0]
        return ‘‘.join(ans)