标签：ash using char* style tar target i++ stream insert
题目见这里
题目并不难,不过一开始我没能理清题意,参考了下这里，明白题目实际是考进制转换(13进制)，外加一个映射(hash)，这当然比较简单啦！需要注意的是，样例中tam(Mars Number)----->13(Earth)，由此可知，以13的整倍数(Earth)出现时，不带‘tret’(earth:0)。
#include <cstdio>
#include <iostream>
#include <map>
#include <cstring>
using namespace std;
struct ptrCmp{
bool operator()(const char *s1, const char *s2) const{
return strcmp(s1,s2)<0;
}
};
int main(){
const char hash[25][5]={"tret","jan","feb","mar","apr","may","jun","jly","aug","sep","oct","nov","dec",
"tam","hel","maa","huh","tou","kes","hei","elo","syy","lok","mer","jou"};
map<const char*,int,ptrCmp>hash1;
int i;
for(i=0;i<25;i++)
hash1.insert(pair<const char*,int>(hash[i],i));
// freopen("Data.txt","r",stdin);
char s[5],s1[5],c;
int n;
scanf("%d",&n);
getchar();
while(n--){
scanf("%s",s);
scanf("%c",&c);
if(c==‘ ‘ || (s[0]>=‘a‘ && s[0]<=‘z‘)){
if(c==‘ ‘) scanf("%s",s1);
if(c==‘\n‘){
int index = hash1[s];
if(index<13) printf("%d",index);
else printf("%d",(index-12)*13);
}
else printf("%d",(hash1[s]-12)*13+hash1[s1]);
printf("\n");
}
else{
int key,k;
key=0,k=0;
while(s[k]) key = 10*key+s[k]-‘0‘, k ++;
if(key<13) printf("%s\n",hash[key]);
else{
printf("%s",hash[key/13+12]);
if(key%13) printf(" %s",hash[key%13]); //不带‘tret‘
printf("\n");
}
}
}
return 0;
}
标签：ash using char* style tar target i++ stream insert
原文地址：http://www.cnblogs.com/520xiuge/p/7140992.html
