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538. Convert BST to Greater Tree 二叉搜索树转换为更大树

时间:2017-07-09 23:58:24      阅读:466      评论:0      收藏:0      [点我收藏+]

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Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.

Example:

Input: The root of a Binary Search Tree like this:
              5
            /              2     13

Output: The root of a Greater Tree like this:
             18
            /             20     13
题意:给出二叉搜索树,每一个节点累加比自己更大的值
解法:根据二叉搜索树的特性可知,按照 右->根->左的顺序遍历节点
  1. # Definition for a binary tree node.
  2. # class TreeNode(object):
  3. # def __init__(self, x):
  4. # self.val = x
  5. # self.left = None
  6. # self.right = None
  7. class Solution(object):
  8. def convertBST(self, root):
  9. """
  10. :type root: TreeNode
  11. :rtype: TreeNode
  12. """
  13. self.helper(root)
  14. return root
  15. sum = 0
  16. def helper(self, node):
  17. if(node):
  18. self.helper(node.right)
  19. node.val += self.sum
  20. self.sum = node.val
  21. self.helper(node.left)






538. Convert BST to Greater Tree 二叉搜索树转换为更大树

标签:一个   solution   arc   lan   roo   sea   1.4   uri   space   

原文地址:http://www.cnblogs.com/xiejunzhao/p/7143630.html

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