标签:idt while wan 背包 hang tab ast name ber
Time Limit: 3000MS | Memory Limit: 30000K | |
Total Submissions: 37762 | Accepted: 12830 |
Description
Input
Output
Sample Input
3 10 1 2 4 2 1 1 2 5 1 4 2 1 0 0
Sample Output
8 4
Source
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<algorithm> 5 using namespace std; 6 int n,m,ans; 7 int a[110],c[110],used[100010]; 8 bool f[100010]; 9 int main(){ 10 while(scanf("%d%d",&n,&m)&&n&&m){ 11 memset(f,0,sizeof(f)); 12 ans=0; 13 for(int i=1;i<=n;i++) scanf("%d",&a[i]); 14 for(int i=1;i<=n;i++) scanf("%d",&c[i]); 15 f[0]=1; 16 for(int i=1;i<=n;i++){ 17 memset(used,0,sizeof(used)); 18 for(int j=a[i];j<=m;j++){ 19 if(!f[j]&&f[j-a[i]]&&used[j-a[i]]<c[i]){ 20 f[j]=1; 21 used[j]=used[j-a[i]]+1; 22 ans++; 23 } 24 } 25 } 26 printf("%d\n",ans); 27 } 28 return 0; 29 }
标签:idt while wan 背包 hang tab ast name ber
原文地址:http://www.cnblogs.com/sdfzxh/p/7153122.html