标签:答案 air http cout pair 枚举 cross bit int
题意:给2个字符串s1,s2,求至少改变s2的多少个字符,才能使s2中包含s1,并输出改变的位置
思路:暴力枚举以每一个位置为开始,和s2匹配,求答案
AC代码:
#include<bits/stdc++.h> #include "iostream" #include "string.h" #include "stack" #include "queue" #include "string" #include "vector" #include "set" #include "map" #include "algorithm" #include "stdio.h" #include "math.h" #define ll long long #define bug(x) cout<<x<<" "<<"UUUUU"<<endl; #define mem(a) memset(a,0,sizeof(a)) #define mp(x,y) make_pair(x,y) #define pb push_back const long long INF = 1e18+1LL; const int inf = 1e9+1e8; using namespace std; const int N=1e5+100; char a[1005],b[1005]; int anss[1005]; int ans=100005,la,lb; int main(){ cin>>la>>lb; cin>>a+1>>b+1; for(int i=0; i<=lb-la; ++i){ int k=0; for(int j=1; j<=la; ++j){ if(a[j]!=b[j+i]) k++; } if(k<ans){ int l=0; for(int j=1; j<=la; ++j){ if(a[j]!=b[j+i]){ anss[++l]=j; } } ans=k; } } cout<<ans<<endl; for(int i=1; i<=ans; ++i){ cout<<anss[i]<<‘ ‘; } return 0; }
标签:答案 air http cout pair 枚举 cross bit int
原文地址:http://www.cnblogs.com/max88888888/p/7163314.html