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【LeetCode从零单排】No.135Candy(双向动态规划)

时间:2017-07-16 19:24:29      阅读:147      评论:0      收藏:0      [点我收藏+]

标签:tom   family   math   动态规划   minimum   lin   mil   higher   ret   

1.题目

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

2.代码

public class Solution {
   	public int candy(int[] ratings){
		int size=ratings.length;
		if(size<=1) return size;
		int[] nums=new int[size];
		for(int i=0;i<size;i++){
             nums[i]=1;
		}
		for(int j=1;j<size;j++){
			if(ratings[j]>ratings[j-1]) nums[j]=nums[j-1]+1;
		}
		for(int m=size-1;m>0;m--){
			if(ratings[m-1]>ratings[m]){
				nums[m-1]=Math.max(nums[m]+1,nums[m-1]);
			}
		}
		int result=0;
		for(int n=0;n<size;n++){
			result+=nums[n];
		}
		
		return result;
   	}
}

/********************************

* 本文来自博客  “李博Garvin“

* 转载请标明出处:http://blog.csdn.net/buptgshengod

******************************************/



【LeetCode从零单排】No.135Candy(双向动态规划)

标签:tom   family   math   动态规划   minimum   lin   mil   higher   ret   

原文地址:http://www.cnblogs.com/tlnshuju/p/7191337.html

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