标签:tom family math 动态规划 minimum lin mil higher ret
There are N children standing in a line. Each child is assigned a rating value.
You are giving candies to these children subjected to the following requirements:
What is the minimum candies you must give?
public class Solution { public int candy(int[] ratings){ int size=ratings.length; if(size<=1) return size; int[] nums=new int[size]; for(int i=0;i<size;i++){ nums[i]=1; } for(int j=1;j<size;j++){ if(ratings[j]>ratings[j-1]) nums[j]=nums[j-1]+1; } for(int m=size-1;m>0;m--){ if(ratings[m-1]>ratings[m]){ nums[m-1]=Math.max(nums[m]+1,nums[m-1]); } } int result=0; for(int n=0;n<size;n++){ result+=nums[n]; } return result; } }
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【LeetCode从零单排】No.135Candy(双向动态规划)
标签:tom family math 动态规划 minimum lin mil higher ret
原文地址:http://www.cnblogs.com/tlnshuju/p/7191337.html