标签：元素 pre ext == 复杂度 efi ant logs init
Given a binary tree
struct TreeLinkNode {
TreeLinkNode *left;
TreeLinkNode *right;
TreeLinkNode *next;
}
Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL.
Initially, all next pointers are set to NULL.
Note:
For example,
Given the following perfect binary tree,
1
/ 2 3
/ \ / 4 5 6 7
After calling your function, the tree should look like:
1 -> NULL
/ 2 -> 3 -> NULL
/ \ / 4->5->6->7 -> NULL
机智，即使是相同的办法，在不同的条件下，可以有优化。比如这题里，想想为啥层序遍历要用ｑｕｅｕｅ，为了找到上一层的下一个元素。如果有了ｎｅｘｔ指针，不用ｑｕｅｕｅ也能找到上一层的下一个元素，得到一个优化解法。 ３０％
/**
* Definition for binary tree with next pointer.
* public class TreeLinkNode {
* int val;
* TreeLinkNode left, right, next;
* TreeLinkNode(int x) { val = x; }
* }
*/
public class Solution {
public void connect(TreeLinkNode root) {
if (root == null) {
return;
}
root.next = null;
TreeLinkNode prevLevelStart = root, prev, cur;
while (prevLevelStart.left != null) {
prev = prevLevelStart;
cur = prevLevelStart.left;
while (prev != null) {
if (cur == prev.left) {
cur.next = prev.right;
} else {
prev = prev.next;
if (prev == null) {
cur.next = null;
} else {
cur.next = prev.left;
}
}
cur = cur.next;
}
prevLevelStart = prevLevelStart.left;
}
}
}
相当与层序遍历，在遍历一层时，把一层里的元素前后连起来。 9% 时间＋空间复杂度: O(n)
/**
* Definition for binary tree with next pointer.
* public class TreeLinkNode {
* int val;
* TreeLinkNode left, right, next;
* TreeLinkNode(int x) { val = x; }
* }
*/
public class Solution {
public void connect(TreeLinkNode root) {
ArrayDeque<TreeLinkNode> queue = new ArrayDeque<TreeLinkNode>();
if (root == null) {
return;
}
int size = 0, i = 0;
TreeLinkNode tmp = null;
queue.offer(root);
while (!queue.isEmpty()) {
size = queue.size();
i = 0;
while (i < size) {
tmp = queue.poll();
if (tmp.left != null) {
queue.offer(tmp.left);
}
if (tmp.right != null) {
queue.offer(tmp.right);
}
if (i != size - 1) {
tmp.next = queue.peek();
} else {
tmp.next = null;
}
i++;
}
}
}
}
116. Populating Next Right Pointers in Each Node
标签：元素 pre ext == 复杂度 efi ant logs init
原文地址：http://www.cnblogs.com/yuchenkit/p/7192626.html
