标签:field find turn esc accept ace enter oss code
Time Limit: 2000MS | Memory Limit: 30000K | |
Total Submissions: 5362 | Accepted: 2634 | |
Case Time Limit: 1000MS |
Description
Input
Output
Sample Input
7 6 1 6 13 E 6 3 9 E 3 5 7 S 4 1 3 N 2 4 20 W 4 7 2 S
Sample Output
52
Hint
Source
#include<iostream> #include<cstdio> #include<cstring> using namespace std; int n,m,x,y,z,head[40002],dad[40002],dis[40003],maxx,maxn,sumedge; struct Edge { int x,y,z,nxt; Edge(int x=0,int y=0,int z=0,int nxt=0): x(x),y(y),z(z),nxt(nxt){} }edge[80009]; void add(int x,int y,int z) { edge[++sumedge]=Edge(x,y,z,head[x]); head[x]=sumedge; } void dfs(int x) { for(int i=head[x];i;i=edge[i].nxt) { int v=edge[i].y; if(dad[x]!=v) { dad[v]=x; dis[v]=dis[x]+edge[i].z; dfs(v); } } } int main() { scanf("%d%d",&n,&m); for(int i=1;i<=m;i++) { char s[4]; cin>>x>>y>>z>>s[0]; add(x,y,z); add(y,x,z); } dfs(1); maxx=-0x7fffff; for(int i=1;i<=n;i++) { if(dis[i]>maxx) { maxx=dis[i]; maxn=i; } } memset(dis,0,sizeof(dis)); memset(dad,0,sizeof(dad)); dfs(maxn); maxx=-0x7fff; for(int i=1;i<=n;i++) { if(dis[i]>maxx) { maxx=dis[i]; } } printf("%d\n",maxx); return 0; }
标签:field find turn esc accept ace enter oss code
原文地址:http://www.cnblogs.com/zzyh/p/7197298.html