605. Can Place Flowers（LeetCode）

标签：tput   which   else   res   ret   etc   style   cout   for   

Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.

Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.

Example 1:

Input: flowerbed = [1,0,0,0,1], n = 1
Output: True

Example 2:

Input: flowerbed = [1,0,0,0,1], n = 2
Output: False

Note:

1. The input array won‘t violate no-adjacent-flowers rule.
2. The input array size is in the range of [1, 20000].
3. n is a non-negative integer which won‘t exceed the input array size.

    1     class Solution {
    2     public:
    3         bool canPlaceFlowers(vector<int>& flowerbed, int n) {
    4         int count = 0;
    5         int len = flowerbed.size();
    6         vector<int> vet(len+2, 0);
    7         for (int i = 0; i < len; i++)
    8         {
    9             vet[i+1]=(flowerbed[i]);
   10         }
   11         for (int i = 0; i < len; i++)
   12         {
   13             if (vet[i] == 0 && vet[i + 1] == 0 && vet[i + 2] == 0)
   14             {
   15                 count++;
   16                 vet[i+1]=1;
   17             }
   18         }
   19         //cout <<count<< endl;
   20         if (n <= count)
   21             return true;
   22         else
   23             return false;
   24         }
   25     };

    

605. Can Place Flowers（LeetCode）

标签：tput   which   else   res   ret   etc   style   cout   for   

原文地址：http://www.cnblogs.com/wujufengyun/p/7197310.html