Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 34   Accepted Submission(s) : 24
Problem Description
As we know, Big Number is always troublesome. But it‘s really important in our ACM. And today, your task is to write a program to calculate A mod B.

To make the problem easier, I promise that B will be smaller than 100000.

Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines.
 
Input
The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file. 
 
Output
For each test case, you have to ouput the result of A mod B. 
 
Sample Input
2 3
12 7
152455856554521 3250
 

Sample Output
2
5
1521
 

#include<stdio.h>
#include<string.h>
char x[1000000];
int main()
{
    int n,i,j,k,a,b,c;
    while(scanf("%s%d",x,&n)!=EOF)
    {
       a=0;
       for(i=0;i<strlen(x);i++)
       {
         a=a*10+x[i]-‘0‘;
         a=a%n;    
       }
       printf("%d\n",a);
    }
    return 0;
}