标签:des names 优先 str min sys interval his schedule
Stall Reservations
Input
Output
Sample Input
5 1 10 2 4 3 6 5 8 4 7
Sample Output
4 1 2 3 2 4
Hint
Time 1 2 3 4 5 6 7 8 9 10Other outputs using the same number of stalls are possible. //!!!
Stall 1 c1>>>>>>>>>>>>>>>>>>>>>>>>>>>
Stall 2 .. c2>>>>>> c4>>>>>>>>> .. ..
Stall 3 .. .. c3>>>>>>>>> .. .. .. ..
Stall 4 .. .. .. c5>>>>>>>>> .. .. ..
开始时间升序排序,从左往右排,不会出现排在队首左边的情况。(贪心)
#include<stdio.h> #include<algorithm> #include<queue> using namespace std; struct Node{ int x,y,no; friend bool operator<(Node a,Node b) { if(a.y==b.y) return a.x>b.x; return a.y>b.y; } }node[50005]; bool cmp(Node a,Node b) { if(a.x==b.x) return a.y<b.y; return a.x<b.x; } int a[50005]; priority_queue<Node> q; int main() { int n,c,i; scanf("%d",&n); for(i=1;i<=n;i++){ scanf("%d%d",&node[i].x,&node[i].y); node[i].no=i; } sort(node+1,node+n+1,cmp); q.push(node[1]); a[node[1].no]=1; c=1; for(i=2;i<=n;i++){ if(q.size()&&node[i].x>q.top().y){ a[node[i].no]=a[q.top().no]; q.pop(); } else{ c++; a[node[i].no]=c; } q.push(node[i]); } printf("%d\n",c); for(i=1;i<=n;i++){ printf("%d\n",a[i]); } return 0; }
Stall Reservations 贪心+自定义优先级的优先队列(求含不重叠子序列的多个序列最小值问题)
标签:des names 优先 str min sys interval his schedule
原文地址:http://www.cnblogs.com/yzm10/p/7212052.html