标签：each man class tin div case else return span
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
简单dp
class Solution { public: int dp[1000] = {0}; int climbStairs(int n) { if (dp[n] > 0) return dp[n]; if (n == 1) return dp[1] = 1; else if (n == 2) return dp[2] = 2; else return dp[n] = climbStairs(n - 1) + climbStairs(n - 2); } };
标签：each man class tin div case else return span
原文地址：http://www.cnblogs.com/pk28/p/7212651.html
