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HDU 1012 u Calculate e【暴力打表,水】

时间:2017-07-21 00:01:54      阅读:186      评论:0      收藏:0      [点我收藏+]

标签:暴力   题目   show   namespace   10个   ext   enter   clu   c++   

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 46844    Accepted Submission(s): 21489


Problem Description
A simple mathematical formula for e is

技术分享

where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 

 

Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
 

 

Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
 

 

Source
分析:暴力打表就好了,因为数据范围只有10个,按照格式打出来就好了,一个简单的求阶层的题目!
下面给出AC代码:
 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 inline double gcd(int n)
 4 {
 5     int sum=1;
 6     for(int i=1;i<=n;i++)
 7         sum*=i;
 8     return sum;
 9 }
10 int main()
11 {
12     cout<<n<<" "<<e<<endl;
13     cout<<"- -----------"<<endl;
14     cout<<0<<" "<<1<<endl;
15     cout<<1<<" "<<2<<endl;
16     cout<<2<<" "<<2.5<<endl;
17     double sum=2.5;
18     for(int i=3;i<=9;i++)
19     {
20         sum+=(1.0/(double)gcd(i));
21         printf("%d %.9lf\n",i,sum);
22     }
23     return 0;
24 }

 

HDU 1012 u Calculate e【暴力打表,水】

标签:暴力   题目   show   namespace   10个   ext   enter   clu   c++   

原文地址:http://www.cnblogs.com/ECJTUACM-873284962/p/7214781.html

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