标签:string http return log target ios iostream 距离 als
给一个迷宫,问从起点到终点存不存在一条长度为T的路径。
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判断(T-当前步数)的奇偶性 和 (终点-当前位置)距离的奇偶性是否相同。
#include <set> #include <map> #include <stack> #include <queue> #include <cmath> #include <vector> #include <string> #include <cstdio> #include <cstring> #include <cstdlib> #include <iostream> #include <algorithm> #define MAX(a,b) ((a)>=(b)?(a):(b)) #define MIN(a,b) ((a)<=(b)?(a):(b)) #define OO 0x0fffffff typedef long long LL; using namespace std; const int N = 8; const int skip[4][2] = { { 1, 0 }, { -1, 0 }, { 0, 1 }, { 0, -1 } }; int m, n, t; int sx, sy, ex, ey; char maze[N][N]; bool vis[N][N]; bool judge(int x, int y){ if (x<0 || y<0 || x >= m || y >= n) return false; if (vis[x][y]) return false; if (maze[x][y] == ‘X‘) return false; return true; } bool dfs(int x, int y, int step){ if (x == ex&&y == ey&&step == t) return true; int tag = t - step - abs(ex-x) - abs(ey-y); if(tag<0||tag&1) return false; for (int i = 0; i<4; i++){ int tx = x + skip[i][0]; int ty = y + skip[i][1]; if (judge(tx, ty)){ vis[tx][ty] = true; if (dfs(tx, ty, step + 1)) return true; vis[tx][ty] = false; } } return false; } int main(){ while (scanf("%d%d%d", &m, &n, &t), m + n + t){ for (int i = 0; i<m; i++) { scanf("%s", maze[i]); for (int j = 0; j<n; j++){ if (maze[i][j] == ‘D‘) sx = i, sy = j; if (maze[i][j] == ‘S‘) ex = i, ey = j; } } memset(vis, false, sizeof(vis)); if (dfs(sx,sy,0)) puts("YES"); else puts("NO"); } return 0; }
标签:string http return log target ios iostream 距离 als
原文地址:http://www.cnblogs.com/redips-l/p/7218131.html